sally can paint house in 4 hr., and john can paint same house in 6 hr., how long will it take 2 paint 2gether?

Answer 1

it's 5 hours

Answer 2

Sally paints houses at a rate of 1 house/4hrs houses per hour

John paints houses at a rate of 1house/6 hrs houses per hour

Together they paint houses at 1/4 + 1/6 houses per hour

or 5 houses in 12 hours 5/12 houses per hour

Hours to paint one house = 1 / (5/12) = 12/5 = 2-2/5 hours 2.4

Answer 3

if sally can paint the house in 4 hrs while john took six,then it will be right to say that sally can paint 1&1/2 house in six which is 1.5x faster than john.using john time as a standard,the 2 of them can do 1+1.5=2.5hrs work in 1 john hr.so 6/2.5=2.4hrs#

Answer 4

So simple. Suppose the surface area of the house is 24x sq unit. Hence Sally's speed is 24x/4 i.e. 6x sq unit per hour. Similarly, John's speed is 4x sq unit/hour. So combined speed is 10x sq unit/hour. Hence to paint the house together, they'll require 24/10 i.e. 2.4 hours i.e. 2 hours and 24 minutes.

Answer 5

5 hrs

Answer 6

5 hrs

Answer 7

Ok. Let me go through this with you step by step.

We start with the equation:

x/4 + x/6 = 1,

where x equals the total time required to paint the house together.

then we multiply by the least common denominator, 24, to cancel out the fractions:

6x+4x = 24

Simplify:

10x = 24

x = 2.4 hours

hope this helps. :)

EDIT: This is the correct answer. The people saying it's five hours are retarded. its simple algebra. if one guy can complete it in four, why would it take him five hours to do it with help?

Answer 8

5 hours

Answer 9

4+6=10/2=5HRS FOR THEM TO PAINT TOGETHER

Answer 10

21/2 hrs.