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A force of 1 n acts on a mass of 1 kg for a time of 1 s.

2006-09-01 01:14:25 · 3 answers · asked by Anonymous in Education & Reference Homework Help

3 answers

F = ma ..... so ..... a = F/m = (1 kg m/s2)/ 1 kg = 1 m/s2

x = x0 + v0t + 1/2at2 .. so... x = 0 + 0 + 1/2 (1 m/s2) (1s2) = 0.5 m


Aloha

2006-09-01 01:23:06 · answer #1 · answered by Anonymous · 2 0

1.) F = ma
1n = 1kg * a
a = 1 m/s^2

2.) a = v/t, thus v = at
v = 1 m/s^2 * 1 sec
v (at 1 sec) = 1 m/s

3.) In 1 second:
d = d0 + v0t + 1/2 * at2
where d0 = initial distance
v0 = initial velocity.

d = 1/2 (1 * 1 ^2) = 1/2 m

However, it could also be noted that the mass will continue on forever if no other forces act on it.

2006-09-01 08:34:05 · answer #2 · answered by ³√carthagebrujah 6 · 0 0

F = ma

2006-09-01 08:15:55 · answer #3 · answered by Embliri Trex 3 · 0 0

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