Alright, I'll start it for you, but you have to finish it yourself.
Basically we have f(x^2). Now, if we were to diffentiate F(x^2), we'd end up with 2xf(x^2), so, what do we do to get rid of that 2x?
2006-09-01 01:24:24
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answer #1
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answered by tgypoi 5
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Go for it. Integration by parts
Doug
2006-09-01 01:06:21
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answer #2
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answered by doug_donaghue 7
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You can try using this useful online integrator: http://integrals.wolfram.com/index.jsp
When I tried inputing your expression inside, I got
Sqrt[Pi/2] * FresnelS[Sqrt[2/Pi] * x]
Although I'm clueless on what that means, I hope this helps.
2006-09-01 02:19:47
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answer #3
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answered by klwh_88 2
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i will rty to do integratin by parts as several say to to that
( btw how old are you ? )
( sin(x^2) ) ' = cos(x^2) *d x^2 = cos(x^2) *2x dx
so Int (sinx^2) dx = x(sinx^2) - Int ( x.(cos(x^2) *2x ) dx )
etc etc etc etc until you have a Int(sometingwith x * sin(x^2))dx
then you an write the Int explicit and you are done
2006-09-01 01:41:20
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answer #4
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answered by gjmb1960 7
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use integration by parts.
2006-09-01 01:32:29
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answer #5
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answered by navigator 1
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You cannot solve this problem in closed form.
2006-09-01 01:54:09
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answer #6
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answered by dutch_prof 4
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Nope,YOU study and find the answer!
2006-09-01 00:54:18
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answer #7
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answered by Anonymous
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2xcos(x^2)
2006-09-01 02:21:25
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answer #8
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answered by gayathri s 1
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