What goes in this equation as the units???

0 ⤊

What goes in this equation as the units???

I'm given an equation: v= c1 e^(-C2t)

Supposedly, I'm to find the units for variables C1 and C2.
Now, I'm wondering if the e^ will do anything to the units...

If not, I have my units as: C1 = m/s and C2 = 1 / s = Hz.

2006-08-31 19:16:56 · 4 answers · asked by Moosehead 2 in Science & Mathematics ➔ Physics

4 answers

No, the e is just a dimensionless multiplier. You are correct.

2006-08-31 19:22:18 · answer #1 · answered by soymilk 2 · 0⤊ 0⤋

'e' doesn't do anything to disturb your units system. Your choice of C1 and C2 are perfectly right.

2006-09-01 02:22:34 · answer #2 · answered by Sana 2 · 0⤊ 0⤋

take the derivative

2006-09-01 02:24:20 · answer #3 · answered by MrZ 6 · 0⤊ 0⤋

...unless, of course, "v" is a voltage.

2006-09-01 04:07:06 · answer #4 · answered by Fred S 2 · 0⤊ 0⤋