2 men bought 36 apples, joe bought 8 times more than sam how many did sam buy?

Answer 1

4 Apples
8*4=32(Joe's Apples) + 4 (Sam's Apples)=36 Total

Answer 2

Here's how you figure the problem out...

The total is going to be 36 because there are 36 apples.
The amount of apples Joe and Sam bought is X because you don't know so you can use any letter as a variable.

Joe bought 8 times more that Sam... That means...
8x + 1x
That equals 9x

Now you know that...

36 = 9x

Divide by 9 to get x by itself...

X = 4

Sam bought 4 apples.

Answer 3

4

Answer 4

Sam bought 4 of course
Joe bought 32 ---8 times more
Together they purchased 36

Answer 5

You're assuming Sam bought apples. Just because the math indicated he could have purchased 4 apples doesn't mean he bought any. I vote that Sam didn't buy any apples and that the 2 men who bought the apples did not include Sam.

Sam bought zero apples, Joe bought 8 apples (which means he bought 8 times more apples than Sam) and the 2nd man who bought apples (along with Joe) purchased 28 apples.

Answer 6

sam bought 4, joe 32

Answer 7

s= sam's amount
j= 8s

8s + s = 36

9s=36

s=4

Answer 8

Answer is 4.
The logic lies in simple math.
Assume Sam has got Y apples, so Joe must have got 8xY i.e. 8Y apples. Now total sum of apples is 36. So we can say
Y+8Y = 36
9Y = 36
Y = 36/9
Y = 4 and that is your answer.

Answer 9

if the no of apples bought by sam is x
then joe is 8x
x+8x=36
x=4
hence the no of apples bought by sam is 4

Answer 10

4 apples

36= 8 * X
X= 4 apples