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6 answers

wow, you must be real smarty guy

2006-08-31 17:40:37 · answer #1 · answered by jobugg257 3 · 0 0

Do you mean the degeneracy of the energy levels of a quantum particle in a Box Potential with infinite walls?
Is so you should find solution of Schroedinger equation for a free particle in a 3d box.
It is not so hard to do! you find K vectors. all K vectors with the same modulus are degenerate in facts the have all the same eigenvalue for the hamiltonian :
1/2 * |K|^2 * h(cut)/ (2* m)
where m is the mass of the particle

2006-08-31 23:31:36 · answer #2 · answered by Randolph C 1 · 1 0

degeneracy of a particle in a 3-dimensional box with cartesian coordinates x,y,z can be found .it requires calculus.

2006-08-31 17:46:52 · answer #3 · answered by TONY 2 · 0 0

For any potential well:

There is no degeneracy between energy levels for different values of the orbital angular momentum quantum number (L) of the particle.
Each energy level of orbital angular momentum quantum number L is (2L+1)-fold degenerate with respect to the magnetic quantum number (M).

This feature is common to all central potentials, both finite and infinite.

2006-09-04 11:49:17 · answer #4 · answered by DrCuprate 2 · 0 0

particular, why not, i'm assuming t is time? i think it would desire to define a element's area relative to whilst it got here approximately. do not question me to tell apart it nevertheless. x, y, z is annoying sufficient. i think, x, y, t might want for use for television & notebook displays, even with the reality that extra advantageous than probably matrices are a quicker way of dealing with the information.

2016-11-23 17:05:25 · answer #5 · answered by pere 4 · 0 0

I just answered this

wait, nevermind, this questions asks something a little bit different. Too much effort my friend.

2006-08-31 17:45:26 · answer #6 · answered by s_e_e 4 · 0 0

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