2006-08-31 17:33:50 · 10 answers · asked by Sue 1 in Science & Mathematics ➔ Mathematics
you can divide them into 8 groups.
First write the prime fatorization of both:
88=2*2*2*11
120=2*2*2*3*5
the common factor in both is 2*2*2=8
2006-08-31 17:39:06 · answer #1 · answered by absynthian 6 · 0⤊ 0⤋
Assuming each person has to get an integer number of crackers and drinks, you have the following solutions:
1 person, 88 crackers & 120 drinks
2 people, 44 crackers and 60 drinks each
4 people, 22 crackers and 30 drinks each
8 people, 11 crackers and 15 drinks each
2006-09-01 08:36:23 · answer #2 · answered by NotEasilyFooled 5 · 0⤊ 0⤋
88 people can have a cracker each and a couple of mouthfuls of the 120 drinks, each, until the drinks are gone. The crackers can't be divided without leaving crumbs, but the drinks are completely fungible, and therefore evenly divisible to any desired accuracy.
Sometimes, the simple math is stultifying. Don't get hung up on what you're "meant" to learn.
2006-09-01 00:46:27 · answer #3 · answered by questor_2001 3 · 1⤊ 0⤋
If there is 88 crackers...and 28... of them do not drink..then..the other 60 crackers that do drink...will have 2 drinks each...then send 1 of the non-drinking crackers to the store for more....that was an easy question
.
2006-09-01 00:44:07 · answer #4 · answered by Freddy D 2 · 1⤊ 0⤋
11 crackers and 15 drinks for 8 people
2006-09-01 00:39:08 · answer #5 · answered by SASHA123 4 · 0⤊ 0⤋
8 people , 11 crackers and 15 drinks
2006-09-01 00:37:25 · answer #6 · answered by Anonymous · 0⤊ 0⤋
The required number of people is 2, 4, or 8
EXPLANATION:
Let the requird number of people be n.
Then by conditions of the problem:
n must divide both 88 and 120
Or, n must divide GCD(88, 120)
Or, n must divide 8
Or, n = 1,2,4,8
Hence the number of people may be 1, 2, 4, 8.
The case of one person is not applicable, as it contradicts the equal split condition.
So, the number of persons is 2, 4 or 8.
2006-09-01 00:57:13 · answer #7 · answered by K Sengupta 4 · 0⤊ 0⤋
8 people----- each will get 11 crackers and 15 drinks
2006-09-01 00:46:00 · answer #8 · answered by whatthe!$#^@%&&~!&15$%^ 2 · 0⤊ 0⤋
give 8 people 11 crackers and 15 drinks each... i dont know
2006-09-01 00:36:42 · answer #9 · answered by brookie5303 3 · 0⤊ 0⤋
the first post is right, you need to find the greatest common factor.
I can honestly say i haven't tried to find the greatest common factor of two Numbers for like 13 years
2006-09-01 00:39:45 · answer #10 · answered by abcdefghijk 4 · 0⤊ 0⤋