2006-08-31 17:09:19 · 9 answers · asked by Sue 1 in Science & Mathematics ➔ Mathematics
with out any thing being leftover....and then how many would each person get?
2006-08-31 17:14:10 · update #1
what if there were only 88 crackers?????
2006-08-31 17:24:34 · update #2
[Edit] You weren't supposed to eat any yourself!! *grin*
2ppl=60d+44c
4ppl=30d+22c
8ppl=15d+11c
Depends if you want the MOST people who can share evenly or the least??? Or if you're after ALL the numbers of people who can share them equally.....
2 ppl = 60 drinks and 45 crackers each
3 ppl = 40 drinks and 30 crackers each
5 ppl = 24 drinks and 18 crackers each
6 ppl = 20 drinks and 15 crackers each
10 ppl = 12 drinks and 9 crackers each
15 ppl = 8 drinks and 6 crackers each
30 ppl = 4 drinks and 3 crackers each
2006-08-31 17:20:15 · answer #1 · answered by muras 3 · 1⤊ 0⤋
It depends on whether the crackers are allowed to be broken into half or not.
However, I assume that none of the crackers are to be broken.
Therefore, the max no of people that can share them would be the highest common factor of 120 and 90, which is 30.
If shared equally among 30 people, each would receive 4 drinks and 3 crackers.
2006-09-01 00:14:37 · answer #2 · answered by klwh_88 2 · 0⤊ 0⤋
30 People. 4 Drinks and 3 Crackers each!
2006-09-01 00:17:09 · answer #3 · answered by nice_libra_guy 6 · 0⤊ 0⤋
30 people
each gets 4 drinks and 3 crackers
2006-09-01 00:29:26 · answer #4 · answered by Blood 2 · 0⤊ 0⤋
30 people , 4 drinks and 3 crackers
2006-09-01 00:34:56 · answer #5 · answered by Anonymous · 0⤊ 0⤋
30 people (4 drinks and 3 crackers each)
2006-09-01 00:14:26 · answer #6 · answered by moondancer629 4 · 0⤊ 0⤋
Split the crackers in half you get 180 crackers and with those many pieces you will have 60 pieces left over.
Is this what you are asking?
Hope it helps
2006-09-01 00:13:30 · answer #7 · answered by natisoccer 2 · 0⤊ 0⤋
30?
2006-09-01 00:13:27 · answer #8 · answered by ray7104 2 · 0⤊ 0⤋
Ninty only
2006-09-01 00:11:53 · answer #9 · answered by Amar Soni 7 · 0⤊ 0⤋