3 logbx = logb 64
The b's are supposed to be subscripts.
2006-08-31 15:26:39 · 6 answers · asked by Gypsy Girl 7 in Education & Reference ➔ Higher Education (University +)
Refering to the 5th answer: If I start with logbx = 1/3 logb 64 how does the 1/3 become an exponent?
Can anyone explain this?
2006-08-31 15:57:10 · update #1
There is a log rule that states:
n logbx = logbx^n
Therefore you can solve for x based on this equation.
In your case
logbx^3 = logb64
another log rule is that:
b ^ (logbx) = x
raise both sides to the power of b and the logs disappear
so,
x^3 = 64
x = 64^1/3 (cubed root of 64)
x = 4
because 4x4 = 16 x4 = 64
basically you need to know the log rules and apply those to solve this.
2006-08-31 17:56:00 · answer #1 · answered by NordicGuru 3 · 3⤊ 0⤋
log bx= 1/3logb 64
logbx= logb 64 to the power of 1/3
logbx= logb 4
therefore, x=4
2006-08-31 15:46:16 · answer #2 · answered by mj 2 · 0⤊ 0⤋
3 logbx = logb 64
x^3 = 64
x = 4
And, yeah. I'm smart and beautiful. lol
2006-08-31 15:43:59 · answer #3 · answered by One_Man_Show 2 · 1⤊ 0⤋
3 logb x = logb (x*x*x) = logb (x^3)
logb (x^3) = logb 64
x^3 = 64
x = 4
2006-08-31 16:03:46 · answer #4 · answered by Anonymous · 0⤊ 0⤋
u mean 3logb4 = logb64
2006-08-31 15:42:21 · answer #5 · answered by cute boy 1 · 0⤊ 2⤋
$1.95
2006-08-31 15:42:40 · answer #6 · answered by Celt Pagan 7 · 0⤊ 2⤋