An ion accelerated through a potential difference of 113V experiences an increase in kinetic energy of 8.16 x 10^-17 J. Find the magnitude of the charge on the ion. Answer in units of C.
2006-08-31 13:54:04 · 2 answers · asked by vem1225 1 in Science & Mathematics ➔ Physics
Interesting
The kinetic energy Ke gained by an ion due to an electric field can be expressed as
Ke = Vq Where
V – potential difference
q – ion charge
therefore q=Ke/V
q= 8.16e-17/113 = 7.22e-19 Coulombs
Note: The mass of the ion is unknown and perhaps erroneously assumed to be zero since ions can be quite massive.
2006-08-31 14:58:36 · answer #1 · answered by Edward 7 · 2⤊ 0⤋
1 electron volt=1.6x10^-19 J. Divide your figure by this and you get 510. Divide this by 113 and you get 4.513 electron charges. 1 electron=1.6x10^-19 C. Multiply this by 4.513 and you get 7.22x10^-19 C. I'm sure the maths is correct but this answer is puzzling as it isn't a whole number of electronic charges.
2006-08-31 14:15:50 · answer #2 · answered by zee_prime 6 · 0⤊ 0⤋