and takes off under a constant net force of 37,000. What is the net force that acts on the plane's 78kg pilot?
2006-08-31 12:42:11 · 4 answers · asked by luna_moon 1 in Science & Mathematics ➔ Physics
college was too long ago, but...
force = mass X accelleraction (F=MA)
solve for the accel. of the aircraft
37,000N=31,000kg (A)
A= 1.19 M/S^2
since the pilot is not moving in relation to the aircraft he should have the same acceleration.
so F=MA
F=78kg * 1.19M/S^2
F=92.82 N
im think thats right but any corrections?
2006-08-31 12:57:03 · answer #1 · answered by gooslegeek 5 · 0⤊ 0⤋
93.097 (Newtons).
At take off the total force is 37,000 (Newtons) acting on a mass of 31,000kg. The force acting on 1 kg is therefore 1.194 (Newtons), .i.e. 37.000 divided by 31,000.
Because the pilot has a mass of 78kg then the force acting on him is 78 x 1.194.
2006-08-31 19:49:03 · answer #2 · answered by Trevor 7 · 0⤊ 0⤋
Net force will remain same. He will be xperiencing the acceleration. F = ma will get you this acceleration
2006-08-31 20:23:23 · answer #3 · answered by Dr M 5 · 0⤊ 0⤋
uh 0 I think because he is inside a closed system and there are no NET forces inside the system if it is not affected from outside
I MAYBE TERRIBLY WRONG ABOUT THIS
2006-08-31 23:27:52 · answer #4 · answered by amandeep s 3 · 0⤊ 0⤋