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Question

how do u find the mean, meadian, and mode of a set of #'s???

Answer 1

Mean
The average of a group of numbers is called the mean.

Median
The middle number of the group is called the median.

Mode
The number that appears the most often in a listing of number.
Range
The range is the difference between the least number and the greatest number.

Answer 2

Mean, median, and mode are three kinds of "averages". There are many "averages" in statistics, but these are, I think, the three most common, and are certainly the three you are most likely to encounter in your pre-statistics courses, if the topic comes up at all.

The "mean" is the "average" you're used to, where you add up all the numbers and then divide by the number of numbers. The "median" is the "middle" value in the list of numbers. To find the median, your numbers have to be listed in numerical order, so you may have to rewrite your list first. The "mode" is the value that occurs most often. If no number is repeated, then there is no mode for the list.

The "range" is just the difference between the largest and smallest values.

Find the mean, median, mode, and range for the following list of values:
13, 18, 13, 14, 13, 16, 14, 21, 13

The mean is the usual average, so:

(13 + 18 + 13 + 14 + 13 + 16 + 14 + 21 + 13) ÷ 9 = 15

Note that the mean isn't a value from the original list. This is a common result. You should not assume that your mean will be one of your original numbers.

The median is the middle value, so I'll have to rewrite the list in order:

13, 13, 13, 13, 14, 14, 16, 18, 21

There are nine numbers in the list, so the middle one will be the (9 + 1) ÷ 2 = 10 ÷ 2 = 5th number:

13, 13, 13, 13, 14, 14, 16, 18, 21

So the median is 14.

The mode is the number that is repeated more often than any other, so 13 is the mode.

The largest value in the list is 21, and the smallest is 13, so the range is 21 – 13 = 8.

mean: 15
median: 14
mode: 13
range: 8

Note: The formula for the place to find the median is "( [the number of data points] + 1) ÷ 2", but you don't have to use this formula. You can just count in from both ends of the list until you meet in the middle, if you prefer. Either way will work.

Find the mean, median, mode, and range for the following list of values:
1, 2, 4, 7

The mean is the usual average: (1 + 2 + 4 + 7) ÷ 4 = 14 ÷ 4 = 3.5

The median is the middle number. In this example, the numbers are already listed in numerical order, so I don't have to rewrite the list. But there is no "middle" number, because there are an even number of numbers. In this case, the median is the mean (the usual average) of the middle two values: (2 + 4) ÷ 2 = 6 ÷ 2 = 3

The mode is the number that is repeated most often, but all the numbers appear only once. Then there is no mode.

The largest value is 7, the smallest is 1, and their difference is 6, so the range is 6.

mean: 3.5
median: 3
mode: none
range: 6

The list values were whole numbers, but the mean was a decimal value. Getting a decimal value for the mean (or for the median, if you have an even number of data points) is perfectly okay; don't round your answers to try to match the format of the other numbers.

Find the mean, median, mode, and range for the following list of values:
8, 9, 10, 10, 10, 11, 11, 11, 12, 13

The mean is the usual average:

(8 + 9 + 10 + 10 + 10 + 11 + 11 + 11 + 12 + 13) ÷ 10 = 105 ÷ 10 = 10.5

The median is the middle value. In a list of ten values, that will be the (10 + 1) ÷ 2 = 5.5th value; that is, I'll need to average the fifth and sixth numbers to find the median:

(10 + 11) ÷ 2 = 21 ÷ 2 = 10.5

The mode is the number repeated most often. This list has two values that are repeated three times.

The largest value is 13 and the smallest is 8, so the range is 13 – 8 = 5.

mean: 10.5
median: 10.5
modes: 10 and 11
range: 5

While unusual, it can happen that two of the averages (the mean and the median, in this case) will have the same value.

Note: Depending on your text or your instructor, the above data set may be viewed as having no mode (rather than two modes), since no single solitary number was repeated more often than any other. I've seen books that go either way; there doesn't seem to be a consensus on the "right" definition of "mode" in the above case. So if you're not certain how you should answer the "mode" part of the above example, ask your instructor before the next test.

About the only hard part of finding the mean, median, and mode is keeping straight which "average" is which. Just remember the following:

mean: regular meaning of "average"
median: middle value
mode: most often

(In the above, I've used the term "average" rather casually. The technical definition of "average" is the arithmetic mean: adding up the values and then dividing by the number of values. Since you're probably more familiar with the concept of "average" than with "measure of central tendency", I used the more comfortable term.)

Answer 3

Say you have the following set of numbers:

0 0 1 6 7 9

The mean is just the average. So, add all the numbers together: 0+0+1+6+7+9= 23, then divide by the amount of numbers that you have. In this case, that is 6. So, the mean is = 23/6 = 3.83

The median is the middle number of the set once you place the numbers in order. If you have an even number of numbers then you average the middle two. So, in this case the middle two numbers are 1 and 6. Add them together and get the average: 1+6=7/2=3.5

The mode is just the number that occurs the most often in the set. So, for this set it is the number 0 since that is in the set twice.

Answer 4

mean = you add them all and divide them by there number

median = The first step in finding the median is to arrange the data in either decreasing or increasing order ( from small to larg or other way ) then you count them and divide the number by tow the number that you get is the class of your number you count and take it
ex : 3 . 4 . 5 .6 . 7
they are 5 digits so 5/2 = 2.5 we take it as a 3
and the third number is =5 is the median
you can have an odd count then it would be
ex = 3 , 4 , 5, 6, 7 , 8
they are 6 digits you divied them by 2 and get 3 so you take the 3rd and the forth and divide them by 2
3rd =5 , 4 th = 6
5+ 6 = 11 so the median is 11/ 2 which is 5.5

and now the mode = The number that occurs most frequently in a set of numbers
ex . 5 , 6, 6 , 6 , 9 , 11 , 11 , 15 the mode here is 6

Answer 5

Mode - the most frequently occurring number within the set

Mean - all the numbers added together, divided by the number of values in the set

Median - the middle number when the set is arranged in numerical order

Answer 6

mean : add numbers together and then divide by the amount of numbers you are dealing with.

median: put all the numbers into order beginning with the smallest to the largest number. the number in the middle is the median.

mode: the most prevalent number.

Answer 7

mean is the average when you add all the numbers then divide it by the number of numbers there are. median , you just put the numbers in order and fing the middle number ansd mode is if you have more than one of the same number.

Answer 8

Mean--is basically the average..meaning you just add all the numbers up and divide by how many numbers there are.

Meadian--Middle what number is in the middle.

Mode--Code..what number/s appears more than once??

Answer 9

median=middle number, mode=number most common, mean=add all numbers up and divide it by how many numbers there are

Answer 10

post the hole q then some may have an answer til then g luck