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I need help factoring these expressions.

1.

((3MN^2 - 3 M)/(N) x ((3M)/(N^2 - 1))
In case this is confusing, those are two fractions being multiplied.

2.

((48B^2 + 8B + 7)/(12B - 1))
Also a fraction (only one this time though)

3.

((x^2 + 4x - 5)/(x^2 - 2x - 3)) + ((2)/(x+1))
This time there are two fractions being added.

If you don't mind, please explain your answer.

I know how to factor. This is a review of what I learned last year and it's not graded. I just cannot get these 3 problems.

If I get an answer I can go back and see how to get to it. I'm not just going to copy answers from anyone without seeing how it was done.

2006-08-31 11:57:20 · 2 answers · asked by allstarbri22 2 in Science & Mathematics Mathematics

2 answers

1.

- 9 M (M - MN^2) / [ (N - 1) N (N + 1) ]

2.

( 48 B^2 + 8 B + 7 ) / (12 B - 1)

3.

(x^2 + 6x - 11) / [ (x - 3) (x + 1) ]

No time for more explanations now, good luck.

2006-08-31 12:02:44 · answer #1 · answered by Pedromdrp 2 · 0 0

((3mn^2 -3m)/(n) x ((3m)/(n^2 -1)

3mn^2-3m factors to 3m *(n^2-1)

So we have 3m(n2^1)/n * (3m)/(n^2-1)
the (n2^1) cancels out to leave
3m/n *3m = 9m^2/n

2. Are you sure the problem is correct?

3. x^2 + 4x - 5 factors to (x-5)(x+1) and x^2 -2x -3 factors to (x-3)(x+1) Does that help?

2006-08-31 19:18:44 · answer #2 · answered by Steve A 7 · 0 0

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