Could someone please show me an expression for Kp in the following
2NO2 -> N2O4
2006-08-31 10:08:31 · 4 answers · asked by RED MIST! 5 in Science & Mathematics ➔ Chemistry
Thank you very much hfshaw.
2006-08-31 10:59:48 · update #1
The equilibrium constant (I assume this is what you are looking for) for the specified reaction is:
Kp = p_N2O4/(p_NO2)^2
where p_N2O4 and p_NO2 are the partial pressures of the N2O4 and NO2, respectively. (Strictly speaking they are the fugacities of these species, but at low pressures one can assume that the fugacities are equal to the partial pressures).
2006-08-31 10:51:49 · answer #1 · answered by hfshaw 7 · 4⤊ 0⤋
you're on purpose. continuously placed the products interior the numerator and reactants interior the denominator, each and every advance to the flexibility of the coefficient that looks interior the previous each and every substance interior the balanced equation. The exception is which you do not often comprise H2O in ok expressions, via fact the main purpose of water is roofed into the ok fee. So, often omit H2O (l) in ok expressions.
2016-12-14 15:42:11 · answer #2 · answered by Anonymous · 0⤊ 1⤋
Kp? I know of Ksp, kon, koff, KI, Ka, Kb. If you're talking about Ke it's products/reactants.
you need to check your terms
2006-08-31 11:12:13 · answer #3 · answered by shiara_blade 6 · 0⤊ 2⤋
whats KP again?
2006-08-31 10:44:17 · answer #4 · answered by Anonymous · 0⤊ 2⤋