Mathematics?

Question

Evaluate (a-b)^2 +bc when a=-2, b+3,and c+4
best answer 32 or 37 or 13 or -13

Simplify (-3/5) (-10X)
best answer -6X or 9X

Write 4/9 as a decimal Place a bar over the repeating digits of the decimal best answer 0.04 or 4.4

Answer 1

Part One ;
(a-b)^2 +bc when a=-2, b+3,and c+4
b+3 = 0 ; b= -3
c+4 = 0 ; c = -4
just pt them in the formula
(a-b)^2 +bc =
(-2-3)^2 + (-3 * -4) = (-5)^ 2 + 12 = 25 + 12 = 37

Part Two;
(-3/5) (-10X) = just divide by ' 5 '
so we have (-3) (-2x) = + 6x

Part Three;
if you use calculator you will see it would be 0.44444 to be continued by '0.4' not '0.04 ' it means a bar over the 4



Good luck.

Answer 2

Evaluate:
(a-b)^2 + b * c
(2 - 3)^2 + 3 * 4
(-1)^2 + 3 * 4
1 +12
13

Simplify:
(-3/5) * (-10x)
Negative * Negative = Positive
(3/5) * (10x)
10 and 5 cancel.
(3)*(2x)
multiply 3 * 2
6x

Write 4/9 as a decimal
4 / 9 = 9 into 4
0.4 (With a bar over the 4)

Answer 3

37,6x,0.04

Answer 4

what the...good job.