simplify (3/y)-(2y+1/3y)+(1/3)?

Answer 1

well look what I've done please ;

step 1 ;
(3/y)-(2y+1/3y)+(1/3) = 3/y -2y - 1/3y+1/3

Here you can multiply by ' y '

y * [ 3/y -2y - 1/3y+1/3 ] = y ((3/y) + y (-2y) + y(- 1/3 y ) + y (1/3 )
3 -(2y^2) -(1/3y^2) +1/3y ;
factor ' y^2 '
3+ y^2 ( - 2 -1/3) + 1/3y = 3 - (7/3 y^2 ) + 1/3y
Or
-7/3y^2 +1/3y +3

Step 2;
now you can multiply by 3 ;
3* [-7/3y^2 +1/3y +3 ] =
3* (-7/3y^2) + 3(1/3y ) + (3*3) =
-7 y^2 + y + 9

GOOD LUCK...

Answer 2

3/y - 2y+1/3y + 1/3
1) change the denomiator to the same. So the common deno is 3y. The second term we don't touch case it has the common deno. So the first term mutliple it by 3 and the third term multiple by y.
(3x3/3xy) - (2y+1/3y) + (1xy/3xy)
= (9/3y) - (2y+1/3y) + (y/3y)
Why it don't open bracket is becoz we have to deal with the - sign.
When opening the bracket, look carefully at the sign in front of it. We need to multiple the - sign into the brackets.
For the first term, there is no sign in front is just open it.
For the second term, there is a - sign so multiple the - sign into the term and u will have -2y-1/3y.
The third term is the same as the first term.
So when the brackets are removed, the equ. will be 9-2y-1+y/3y.
Why i combine it all is becoz i have the common denomiator.
Thus work out ya steps and u will have 8-y/3y.

Answer 3

Multiply by Y
3-2y^2+1/3+y/3
Multiply by 3
9-6y^2+1+y
Combine like terms
-6y^2+y+9

Answer 4

if by this you mean

(3/y) - ((2y + 1)/(3y)) + (1/3)

Multiply everything by 3y

(9 - (2y + 1) + y)/(3y)

(9 - 2y - 1 + y)/(3y)

(-y + 8)/(3y) or -(y - 8)/(3y)

Answer 5

get a common denominator first
(9/3y)-(6y^2/3y+1/3y)+(y/3y)
then you can combine the fractions removing the ()
(9-6y^2-1+y)/3y
and combine like terms
(-6y^2+y+8)/3y

Answer 6

(8-y)/3y y shouldn't be 0

Answer 7

ASK QUESTION TO GOOGLE THEY HAVE THE ANWSER I JUST PUT YOUR QUESTION TO THEM PAGES OF ANWSERS AND HOW TO SOLVE.

Answer 8

math sucks!

Answer 9

that is already pretty simple

Answer 10

No, do your own homework!