If y varies inversely as x and y = 8 when x = 4, find y when x = 16.?

Answer 1

well if they vary inversly, that means when one goes multiplied by 2, then the other divides by 2 for example. So, if you have y=8, when x=4 and you take and multiply x by 4, making it =16, then y is going to do the opposite, divide by 4 therefor 8/4=2 so 2 will be your new value for y

y=2

Answer 2

The expression for the statement is:

y=k/x, where k is the constant of proportionality.

So when y =8 and x =4,
We get,
8=k/4
32=k

Since k is a constant it will remain the same for the statement 'y varies inversely as x'.

Now when x = 16,
y= 32/16
y=2

Answer 3

Varies Inversely

Answer 4

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RE:
If y varies inversely as x and y = 8 when x = 4, find y when x = 16.?

Answer 5

if y=a/x
when y=8,x=4
then
8=a/4
therefore
a=32
if x=16,then
y=a/4
hence y=32/16
then y=2
answer:-y=2

Answer 6

If y varies inversely as x, when x increases fourfold,
y must decrease fourfold. So y = 2 when x = 16.

Answer 7

Varying inversely is the opposite of varying directly.
You can solve direct proportions by dividing using:
x1/y1 = x2/y2, where x1, y1 are the first set of numbers and x2, y2 is the second set.
Likewise, you use mulitiplication if they vary inversely:
x1y1 = x2y2

In this case:
(4)(8) = (16)(y)
y = 2

IF they had varied directly, you could have solved them like this:
4/8 = 16/y
y = 32

Answer 8

The required value of y is 2

EXPLANATION:

y=c/x, where c is a constant
so, 8 = c/4, giving c =32.
Accordingly, y = 32/x
As x = 16, we obtain:
y = 32/16 = 2

Answer 9

y = k/x

8 = k/4
k = 32

y = 32/16
y = 2

ANS : 2

Answer 10

32