well dear f(x) = 3x^2 - 4x - 5
in general form we have
ax^2 + +bx + c =0
so if a = +3 , b= -4 & c = -5
∆ = b^2 - 4ac
∆ = (-4^2) - 4* 3* -5 = 16 +60= 76
now
x1 = (-b + √∆) / 2a = ( -(-4) + √76 )/ 2*3 = 4+7.45 / 6
x1 = (-b - √∆) / 2a = ( -(-4) - √76 )/ 2*3 = 4- 7.45 / 6
2006-08-31 11:05:15
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answer #1
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answered by sweetie 5
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To use the quadratic formula, your equation must be in the form:
ax² + bx + c = 0
Your equation is already in this form
3x² + (-4)x + (-5) = 0
So you can easily determine a, b and c (3, -4, -5).
Now you just plug that into the quadratic formula. It's hard to type this all on a single line here and make it readable, but it looks something like this:
x = [ -b ± â(b²-4ac) ] / 2a
If you were writing this on your paper, you would make a fraction with -b ± â(b²-4ac) in the numerator and 2a in the denominator.
Now, just plug in the values above for a = 3, b = -4, c = -5
Numerator: -b ± â(b²-4ac) = -(-4) ± â( (-4)² - 4(3)(-5) )
Denominator: 2a = 2(3)
Numerator: 4 ± â(16 + 60)
Denominator: 6
Numerator 4 ± â76
Denominator: 6
Now â76 can be simplified by factoring out a 4:
Numerator 4 ± â4 * â19
Denominator: 6
Numerator 4 ± 2 * â19
Denominator: 6
Divide top and bottom by 2:
Numerator 2 ± â19
Denominator: 3
So the answers are:
x = (2 + â19) / 3
x = (2 - â19) / 3
Or simply:
x = (2 ± â19) / 3
The decimal values are:
x â 2.120... or -0.7863...
2006-08-31 13:49:27
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answer #2
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answered by Puzzling 7
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3x²-4x-5=0 is in the standard form ax²+bx+c=0 so it's
plug 'n play
x = (-b±â(b²-4ac))/2a and
x = (4±â(16+60))/6) = (4±â76)/8 = 1/2 ± â19/4
Doug
2006-08-31 13:48:32
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answer #3
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answered by doug_donaghue 7
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You have to break the equation up into a, b & c.
In your case:
a = 3
b = -4
c = -5
Then plug them into the quadratic formula found here (it may be confusing to type it out):
http://mathworld.wolfram.com/QuadraticFormula.html
Use the one that is all over "2a"
Simply plug in the values and solve it.
2006-08-31 13:44:26
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answer #4
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answered by dreft 2
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a=3 b=(-4) c=(-5)
(-b) +/- (sq root(b^2-(4ac))) divided by (2a)
(-(-4)) +/- (sq root(76)) divided by 6
4 +/- 2(sq root(19))/6
(2 +/- (sq root(19)))/3
about 2.12 or (-.79)
2006-08-31 13:44:40
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answer #5
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answered by Anonymous
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Do your own homework!
2006-08-31 13:47:00
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answer #6
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answered by Anonymous
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