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We know that the size of nucleus is very-very-small compared to the orbit of the electrons.

1 litre of water normally weight 1kg.

Hypothetically lets say we are able to remove these spaces and just have one litre of matter just created by packing only the nucleus next to each other with no space, lets just assume we strip off all the electrons. (do not worry about H2O, just think we are dealing with the nucleus of Oxygen)
I guess it might be too damn heavy......but would like to hear from experts.

2006-08-31 05:49:37 · 11 answers · asked by Anonymous in Science & Mathematics Physics

11 answers

What you are describing is a "Neutron Star", a collapsed star where all the electrons have been pushed inside the neucleus and combined with the protons to form neutrons. The entire star is ONE gigantic neucleus with trillions upon trillions of neutrons pressed tightly against one another. So there would be "almost" no space at all between the neutrons.

Of course, even a neutron itself is made of mostly space because it is composed of 3 quarks, and the quarks are much smaller than the neutrons. A quark is about 10^-16cm or 1/1000 the size of a proton or neutron. And if you believe that quarks are made of strings, then strings are even much much smaller than a quark. A string is 10^-33 cm!!!

So we can conclude that atoms, or nucleus of atoms, or neutrons/protons, or quarks, are made up mostly of EMPTY space.

2006-08-31 06:04:26 · answer #1 · answered by PhysicsDude 7 · 1 0

Theoretically, such a substance would have an incredible density as you would be able to pack much more nuclear mass into a smaller area with the absence of the elctron clouds of all those atoms. This is only theoretical because the electrons present in those clouds do a number of things for the atom, the most important of which (for your hypothetical situation) is to stabilaze and balance the positive charges of the protons in each nucleus. If you remove the electrons, the nucleus would lose its stability and the positive charges of the protons would cause the nucleus to be torn asunder. Even allowign for some sort of adhesive effect to hold the nucleus together, you would then be unable to pack so many positively charged nuclei together, as their charges would repel each other, preventing the density for which you are looking.

However, it may be theoretically possible to compress the electrons orbits to the nuclear boundary, thus reducing the amount of space in an atom. In some ways, that it the theoretical model of a black hole, in which matter is compressed to a near infinitesimal state. In fact, some physicists posit that that gravitational forces of a black hole actually compress the classic atomic particles so much that they overlap and share space as the quarks which in turn make up protons, neatrons, and electrons actually may be compressed in some way. This brings up meson, baryons, and leptons, and these all exist in a purely theoretical modality.

This then becomes the classic question, "How many angels can dance on the head of a pin?"

2006-08-31 06:06:33 · answer #2 · answered by mr_cupp_olmc 1 · 0 0

Once you strip the electrons and pack all the nuclear material together, and assuming for the moment that protons and neutrons have the same mass (it's pretty close), then what you've described is the basic neutron star. According to one source, that's a bit more than 10^14 times the density of water, or about 10^8 metric tons/mL.

2006-08-31 06:01:35 · answer #3 · answered by questor_2001 3 · 0 1

Yeah it would be heavy and dense. Essentially that is what a Neutron Star is. The core of a very large star collapses, crushing itself beyond the point where the electron shell is distinct.

BTW at one point in time the definition of the metric kilogram 1kg was the weight of 1 litre of pure H2O. and at another point in time the definition of a litre was 1kg of water. Now,,,, who knows.

2006-08-31 06:43:39 · answer #4 · answered by Ken B 1 · 0 0

Ok, hypothetically, of course:

If we were able to pack only the nucleus of atoms, we would have the conditions as it is assumed to be in black holes, (that means density equals a value towards infinity) , and we wouldn't be able to carry away only a thimble full of nucleus.
Actually, we hadn't enough atoms on earth to fill just one thimble. Our sun is just enough to fill one.
In deed highly hypothetically :-)

One more, if we, hypothetically, could control such conditions (as like as removing space within the atoms, then we wouldn't have any energy problems, because to be able to controll such forces, we must be able to work with a singularity ... but if we can work with such thing, we can also gain nearly unlimited energy from it (unlimitad in a human sense, not in the measurement sclae of the universe, of course)

2006-08-31 06:08:13 · answer #5 · answered by jhstha 4 · 0 0

as a fashion to have colour, there might desire to be some replace interior the orbit interior the atomic point of the electron orbiting a nucleus of an atom, however the vulnerable nuclear forces in area an atom do not do something like that to an aton, subsequently there is not any electromagnetism, subsequently, NO colour.-

2016-11-23 16:12:49 · answer #6 · answered by defibaugh 4 · 0 0

Yes, that would be a neutron star, where all the space is gone, no atoms left, the protons and electrons merged into neutrons. The next most dense would be a black hole.

2006-08-31 06:58:28 · answer #7 · answered by Anonymous · 0 0

Your question is irellevent but it would make such a gigantic and unstable nucleus that an H bomb would seem like a firecraker!

2006-08-31 05:59:03 · answer #8 · answered by THE CAT 2 · 1 0

That might be dense enough to form a black hole.


Doug

2006-08-31 06:02:28 · answer #9 · answered by doug_donaghue 7 · 0 0

if u remove its space it wouldnt become heaveir but it will take smaller volume.

2006-08-31 06:01:55 · answer #10 · answered by merdad b 2 · 0 0

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