Do you know the answer and how to work this problem? A lottery has 52 numbers. How many ways can 6 of the numbers be chosen? The numbers are selected without replacement and order does not matter.
2006-08-31 05:01:45 · 10 answers · asked by Sad Mom 3 in Education & Reference ➔ Higher Education (University +)
its the nCr button on your calculator
so 52C6
works out to be
20358520
2006-08-31 05:09:03 · answer #1 · answered by Anonymous · 0⤊ 0⤋
14,658,134,400 over 14 billion combinations. the first ball can be any of the 52 numbers, the next ball can only be one of 51 (52 minus the one already out) and so on until you get six balls.
for the record, when the order doesn't matter (like lottery) its called combinations, when it does its called permutations.
now you can see why its so hard to win.
2006-08-31 12:13:04 · answer #2 · answered by eliaszaga 2 · 1⤊ 0⤋
I think it would be 52+51+50+49+48+47
First you'd have 52 numbers than after you pick a number you'd have 51, than after you pick another you'd have 50. This comes out to 297.
2006-08-31 12:09:00 · answer #3 · answered by Lillith 4 · 0⤊ 1⤋
as long as they can not be replaced (used twice) 52 * 51 * 50 * 49 * 48 * 47 = 14,658,134,400 possibilities
2006-08-31 12:08:18 · answer #4 · answered by brett.brown 3 · 2⤊ 0⤋
52 raised to the 6th power.
2006-08-31 12:06:46 · answer #5 · answered by Angel Eve 6 · 0⤊ 0⤋
52!/ 6! x 46!
2006-08-31 13:41:44 · answer #6 · answered by Anonymous. 2 · 0⤊ 0⤋
Combinatorics!
r = number picked
n = possible pick pool
T = n! / r!(n-r)!
T = 2.04 x 10E7 non-repeating combinations
2006-08-31 12:15:49 · answer #7 · answered by Professor 3 · 1⤊ 0⤋
(52x51x50x49. . . )6
2006-08-31 12:07:53 · answer #8 · answered by imnotbtami 5 · 0⤊ 0⤋
Wouldnt it be 52x51x50x49x48x47
2006-08-31 12:05:22 · answer #9 · answered by Rez 5 · 2⤊ 0⤋
um...193
2006-08-31 12:04:15 · answer #10 · answered by gymnastics617 2 · 0⤊ 0⤋