A ball is thrown downward (not dropped) from the top of a tower. After being released, its downward acceleration will be
a. greater than g.
b. exactly g.
c. smaller than g.
2006-08-31 04:36:53 · 15 answers · asked by Anonymous in Science & Mathematics ➔ Physics
B) exactly g
the logic...
while the ball is in your hand being accelerated, the force is greater than g, but this is asking about after the release. after the release the ball isnt being accelerated by your hand anymore. the only acceleration comes from gravity, thus... B is the correct answer and remains the correct answer until terminal velocity is achieved (max velocty possible in the free fall)
2006-08-31 04:39:31 · answer #1 · answered by Anonymous · 1⤊ 1⤋
Exactly g. Once the ball is released there is no additional forces acting on the ball. The additional force present in the ball being thrown ends at the point of release. Up to that point more or less than g can be an outside factor but not after release.
2006-08-31 04:42:23 · answer #2 · answered by fstopf4 4 · 1⤊ 0⤋
The acceleration would be exactly g.
the velocity would be higher than a ball that was dropped until it reached terminal velocity, and the thrown ball would hit the ground first, but the acceleration would be the same in between release and reaching terminal velocity.
2006-08-31 04:45:57 · answer #3 · answered by . 2 · 0⤊ 0⤋
It's greater then g on the moment of realease. After that the acceleration will slow down till g - drag
2006-08-31 04:45:49 · answer #4 · answered by mc2_is_e 2 · 0⤊ 0⤋
B.
There is nothing acting on the ball except gravity once it is released. At that point all acceleration is caused by gravity so it's going to accelerate at G
Unless you want to inlcude air resiastance then it is C.
2006-08-31 04:39:46 · answer #5 · answered by Scott A 2 · 3⤊ 0⤋
EQUAL TO G assuming no air friction.
acceleration is produced by a force constantly acting on the object.
when u throw an object, once it leaves ur hand, that is it. no more force is on it. it moves with its own velocity [Newton's first Law].
However, here, an additional force is the force due to gravity and it is always there.
so the acceleration is equal to g
2006-08-31 05:17:15 · answer #6 · answered by MobiGuru 2 · 0⤊ 0⤋
the acceleration will be equal to g until terminal velocity is met (when the force of air pressure = force of gravity) at which point it will have a constant speed with no acceleration.
2006-08-31 04:40:38 · answer #7 · answered by bretttwarwick 3 · 0⤊ 0⤋
b is right ans. when the ball is released it come under the gravitational field,its is accelerated due to gravity .so its acceleration should be equal to g.if we put any magnet around it then ans is c ,if air resistance is not ignore then ans is c
ok i hope you understand
2006-08-31 05:03:02 · answer #8 · answered by Kirat K 2 · 0⤊ 0⤋
A. greater - unless its terminal velocity happens to equal g
2006-08-31 04:39:39 · answer #9 · answered by e fitz 4 · 0⤊ 1⤋
Assuming G is gravity, greater than g.
2006-08-31 04:40:13 · answer #10 · answered by can2gone 3 · 0⤊ 0⤋