Peremiter
6 inches
Area
2inches square
2006-08-31 04:09:16
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answer #1
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answered by Moonlight Rose 3
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If the height is 2, then a 30°-60°-90° triangle formed by the height would have a short side of [2 / (â3)], or 2â3 / 3. The hypotenuse (which is one side of the equilateral triangle) is twice that, thus 4â3 / 3.
A = bh / 2
A = (4â3 / 3)(2) / 2
A = 4â3 / 3
P = 3(4â3 / 3)
P = 4â3
2006-08-31 11:18:43
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answer #2
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answered by Louise 5
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ok we have an equilateral triangle
let's name the height with ha and its sides with a, b and c,from here results that a=b=c and that ha=2=aâ3/2 so aâ3=4
a=4/â3=4â3/3
the area is A=a*â3/4=16â3/3¤1/4=4â3/3 (* means here 2 and ¤ means multiplication)
the perimeter is P=(4â3/3)¤3=12â3/3=4â3
so the final result is:A=4â3/3 and P=4â3
2006-08-31 11:49:24
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answer #3
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answered by denise p 4
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The ratio of the height to the base of an equilateral triangle is
sqrt3 : 2 which is the same as 1 : (2(sqrt3)/3).
Here we have height of 2 which implies that the base is
4(sqrt3)/3.
Therefore the area of this triangle is 0.5 *((4sqrt3)/3))*2
=4(sqrt3)/3.
The perimeter= 3*4(sqrt3)/3 =4sqrt3
2006-08-31 11:24:08
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answer #4
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answered by bassbredrin 2
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h = 2
If we draw the height we get a 30 by 60 by 90 triangle
applying trigonometry we get the value 2/sqrt3 as the shorter side and 4/sqrt3 as the hypotenuse
the hypotenuse of the newly made triangle is the side of the equilateral triangle so the perimeter would be
p = 3 * (4/sqrt3)
p = 12/sqrt3
The area would be bh/2
a = ((4/sqrt3) * 2)/2
a = 4sqrt3
Tada!!!
2006-08-31 11:11:31
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answer #5
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answered by Hi-kun 2
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You must use the ratios that exist in 30-60-90 degree triangles to figure this out. Each side has a length of 4sqrt3/ 3 which makes :
p = 4sqrt3
a = 4sqrt3 / 3
2006-08-31 11:21:22
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answer #6
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answered by MollyMAM 6
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perimeter= 3 root 2
area= root 2
2006-08-31 11:37:18
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answer #7
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answered by Anonymous
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given the height = 2 then let the sides = x
from pythogras = x squared - 4 -(0.5 *x) = 0
solve = x = square root of 3
perimeter = 3*square root of 3(in normal units)
area = 0.5 * square root of 3 * 2 = square root of 3 (in square units)
2006-08-31 11:58:50
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answer #8
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answered by petcom_jm 1
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Perimeter = 6.92820323
Area = 2.30938721
2006-08-31 11:28:43
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answer #9
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answered by Anonymous
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h = a * sqrt(3)/2
2 = a * sqrt(3)/2
4 = a * sqrt(3)
4/sqrt(3) = a
a = (4sqrt(3))/3
a = (4/3)sqrt(3)
P = 3a
P = 3((4/3)sqrt(3))
P = 4sqrt(3)
Area = a^2 * sqrt(3)/4
Area = (16/3) * sqrt(3)/4
Area = ((16/3)/4)sqrt(3)
Area = ((16/3)/(4/1))sqrt(3)
Area = ((16/3)*(1/4))sqrt(3)
Area = (16/12)sqrt(3)
Area = (4/3)sqrt(3)
Perimeter = 4sqrt(3) or about 6.928
Area = (4/3)sqrt(3) or about 2.309
2006-08-31 13:14:58
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answer #10
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answered by Sherman81 6
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