A rectangular piece of paper ABCD 6cm by 4cm is folded such that A meets C and a crease is formed.Find the length of the crease formed.
2006-08-31 01:16:29 · 4 answers · asked by Rohit C 3 in Science & Mathematics ➔ Mathematics
2*52^(1/2)/3 = 4.8cm
2006-08-31 01:48:23 · answer #1 · answered by Anonymous · 0⤊ 0⤋
The crease is the diagonal of the original rectangle, which by the Pythagorean Theorem equals Squareroot of (6^2 + 4^2) = Squareroot of (36 + 16) = Squareroot of (52).
2006-08-31 08:20:08 · answer #2 · answered by fcas80 7 · 0⤊ 1⤋
ans 2(square root of 13) or about 6.666cm use the Pythagorean Theorem ( a squared + b squared = c squared) hence 6 squared or 6 x 6 + 4 squared or 4 x 4 = 36 + 16 = 52 ; c squared = 52 c = the square root of 52 or 2 times the square root of 13 ; which is about 6. 66.....
2006-08-31 08:43:16 · answer #3 · answered by packhunt 2 · 0⤊ 0⤋
4.83 centimeters. (approximately) The person who answered first misunderstood the question, I think.
2006-08-31 08:26:30 · answer #4 · answered by Anonymous · 0⤊ 0⤋