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six similar blouse and 4 similar skirts cost $191.i bought 4 such blouses and 2 such skirts and paid $108.How much did a blouse cost?

2006-08-30 23:01:43 · 15 answers · asked by Anonymous in Science & Mathematics Mathematics

show your workings

2006-08-30 23:04:07 · update #1

15 answers

Let me know if you don't understand something, since thats the important part. Most people will just simply multiply the second equation by 2 and simply subtract them. This may be the lesson, but since when you get further into mathematics it's not always this easy, I'll do it the surefire way.

First,

(X = blouses, Y = Skirts)
6x + 4y = 191 (First equation they gave you)

3x + 2y = 95.50
2y = -3x + 95.50
y = -3/2x + 47.75

Substitute what you now have for 'y' into the other one

4x + 2y = 108 (Second equation they gave you)

4x + 2(-3/2x + 47.75) = 108
4x - 3x + 95.50 = 108
x = 108 - 95.50
x = 12.5

Since x was the blouses: $12.50

P.S. Personally, I think it would be easier if we all just ran around nude.

2006-08-30 23:10:49 · answer #1 · answered by Seraphim 3 · 2 3

Let
b = cost of each blouse
s = cost of each skirt


Since 6 blouses and 4 skirts is $191, ("and" and "is" in maths are "plus" and "equals," respectively)
6b + 4s = $ 191

Similarly, since 4 blouses and 2 skirts is $108,
4b + 2s = $ 108

We now have 2 equations
6b + 4s = $191
4b + 2s = $108

There are actually many ways of solving this, but I prefer elimination method: If we divide the second equation by 2, we get
6b + 4s = $191
2b + s = $54

If we multiply -3 to the second equation again, we get
6b + 4s = $191
-6b - 3s = -$162

Now, we add both equations,
s = $29

To solve for b,
2b + s = $54
2b = $54 - s
b = ($54 - s)/2
b = ($54 - $29)/2
b = ($25)/2
b = $12.50

Therefore, a blouse costs $12.50. ^_^
^_^
^_^
^_^

2006-08-31 00:19:49 · answer #2 · answered by kevin! 5 · 0 0

Let B = cost of a single blouse
Let S = cost of a single skirt

Based on Given:

6B+4S=$191
4B+2S=$108

you have 2 distinct equations and 2 unknowns so the problem is solvable.

4B+2S=$108
-4B= -4B (subtract -4B from each side)
(4B+2S)+(-4B)=$108+(-4B)
2S=$108-4B
divide both sides by 2
2S/2= ($108-4B)/2
therefore S= $54-2B
substitute in for S on the 1st equation
6B+4S=$191
S= $54-2B
therefore 6B+4($54-2B)=$191
simplify using order of operations
6B+$216-8B=$191
$216-2B=$191
subtract $216 from each side
-2B=$191-$216= -$25
divide both side of the equation by a -2
-2B/-2= -$25/-2
B=$12.50
which means that S=$54-2B =$54-$25=$29
then check your answer by substituting back 2nd equation
4B+2S=$108
4($12.50)+2($29)=$108
$50+$58=$108
$108=$108 answer checks out B=$12.50

always use "units" (in this case $) and always check your answer.

Additional - You didn't state what "math class" you are taking. I taught intermediate algebra at two different colleges. While I did skip a couple of steps, if I was asking a student to show their work, this would suffice for an intermediate algebra class. I would be checking people's answers especially for use of "units". It shows a more complete knowledge of what's going on by the student and to be honest, often you can use units to figure out how to solve the problem.

2006-08-30 23:28:44 · answer #3 · answered by Spiritual but not religious 4 · 2 0

easy:

let x be the price of the blouse, and y the price of the skirt

first statement translates as:
(1) 6x + 4y = 191

and second statement as:
(2) 4x + 2y = 108

If you multiply (2) by 2, you'll get
(3) 8x +4y = 216

From (3) you can subtract (1) in order to eliminate y:
(8x - 6x) +(4y - 4y) = 216 - 191

Which becomes
2x = 25

So
x = 12.5

So the blouses cost 12.5 dollars apiece.

Now you use this value in (2), you get:
4(12.5) + 2y = 108

50 + 2y = 108
2y = 58
y = 29

so the skirt costs 29 dollars.


This being said, based on my experience of stores selling women's apparel, I'd say that those blouses seem a bit too cheap, compared to the skirts, no?

Hope this helps

a

2006-08-31 01:02:12 · answer #4 · answered by AntoineBachmann 5 · 0 0

Very Simple.
Firstly, a blouse=y 4x+6y =191 (1)
a skirt =x 2x+4y =108

2x+4y =108 x-2
-4x-8y =-216 (2)
(1)+(2)
-2y =-25
y =12.5 (each blouse)

From,(1). 4x+6(12.5) =191
4x =116
x =29 (each skirt)

You want to check,
4(29)+6(12.5) =191
2(29)+4(12.5) =108

2006-08-30 23:19:56 · answer #5 · answered by Amrouch 2 · 1 1

let cost of 1 blouse=x
and let one skirt cost=y

according to Q
6x+4y=191 (take as equation 1)

also 4x+2y=108 (take as equation 2)

multiply equation (2) by 2 to get
8x+4y=216 (equation 3)

subtract (3) from (1) to get
-2x = -25
hence x=12.5$

therefore cost of one blouse= 12.5$

2006-08-30 23:12:51 · answer #6 · answered by ssuasw 3 · 1 1

Blouse = a
Skirt = b

6a + 4b = 191 -----(1)
4a + 2b = 108 ===========>8a + 4b = 216 -----(2)

(2) - (1) ======> 8a - 6a + 4b - 4b = 216 -191
2a = 25
a = 12.5

2006-08-30 23:12:51 · answer #7 · answered by Tsk_Master 2 · 1 2

Blouse is $12.5
Skirt is $29

2006-08-30 23:11:33 · answer #8 · answered by VIDYANAND A S 3 · 1 1

I never tried a blouse or skirt :-)
but answer is $12.50 each blouse.

2006-08-30 23:16:53 · answer #9 · answered by kiran 2 · 1 1

6b+4s=191
4b+2s=108 - double this and we get 8b+4s=216, then substract the first equation and we get 2b=25, 1b=12,5

2006-08-30 23:12:11 · answer #10 · answered by nelabis 6 · 0 1

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