Does the water level IN THE POOL go up, down, or stay the same.
This is one of my all time favorite physics questions. Robert Oppenheimer got it wrong. You must justify your answer for credit. First one wins 10.
2006-08-30 19:06:11 · 16 answers · asked by selket 3 in Science & Mathematics ➔ Physics
So far, raredawn is the closest but the mass of the rock doesn't change and the boat and guy are still in the pool after he dropst the rock in.
2006-08-30 19:20:56 · update #1
Ding ding ding. injanier is our winner.
Very good. Everyone should read that answer and understand it. It is an incredibly elegant solution. It also happens to be the right one.
2006-08-30 19:28:04 · update #2
The water level will go down. In the boat, the rock displaces a volume of water equal to the weight of the rock. In the water, it only displaces its own volume. Since the rock is denser than water, the volume of water equal to the weight of the rock is greater than the volume of the rock, so the rock in the water displaces less water than when it's in the boat.
2006-08-30 19:24:27 · answer #1 · answered by injanier 7 · 0⤊ 0⤋
I'm going to say the water level in the pool goes down. When the rock is in the boat, the boat is heavier and displaces more water. When the rock is tossed overboard, the water level rises due to the rock displacing water equal to its volume, but the boat is lighter by the weight of the rock, thus displaces less water. Ultimately, the bottom of the pool supports some of the weight of the rock, whereas before, the water supported the entire weight of the rock.
If I get this wrong, then I guess I'm in good company!
2006-08-30 19:16:33 · answer #2 · answered by Y Answerer 6 · 0⤊ 1⤋
The water level will go down. The weight of the rock would push the large boat down into the water causing the water level to rise,. When the weight in the boat is reduced there is less mass in the water causing the water level to rise. Even though the weight of the rock will still be in the water is it not weight that causes water level to rise but mass added to the water. the rock by itself has less mass then the boat with the rock in it
2006-08-30 19:15:06 · answer #3 · answered by raredawn 4 · 1⤊ 0⤋
it will make a splash and the rock will go straight down to the bottom due to gravity....meanwhile it will cause a small ripple/wave like effect and the water will drop a bit in level and then rise up a bit in equally term with the weight of the rock..but most pool will have a section where water is allowed to flow out if the pool is over the contained level...so, basically the pool will still be at the same level as before...
2006-08-30 19:16:30 · answer #4 · answered by jims_bong 5 · 0⤊ 1⤋
i would imagine that if he drops the rock in the pool, that the water will rise to compensate for the displacement..even if it's very minute..but, if he drops the rock on the side of the pool, the water will stay the same because he did not drop it in the water...or, if the rock was covering a hole in the boat and he took it off to drop it in the water, the water would go down because it would now be going into the boat
2006-08-30 19:15:53 · answer #5 · answered by ♥ Callie ♥ 4 · 0⤊ 1⤋
The water level goes down. When in the boat, the rock displaces a volume of water equal to the rock's weight. When in the water, the rock displaces a volume of water equal to the rock's volume. Since the rock is denser than water, the volume displaced decreases and the water level falls.
2006-08-30 19:24:55 · answer #6 · answered by S S 2 · 0⤊ 1⤋
even as the rock is contained in the canoe, the canoe displaces an volume of water equivalent in weight to the burden of canoe and its shipment. For purely the rock, which could be say 5 situations its volume's properly worth of water. once you throw the rock overboard, the quantity of water displaced through the further weight of the rock contained in the canoe would get replaced through in ordinary words the quantity of the rock, and hence the water element will drop in accordance to about 4 situations the quantity of the rock. i wager...
2016-12-06 00:46:37 · answer #7 · answered by atwater 3 · 0⤊ 0⤋
um. that depends on the density of the rock . if the man. is holding a one ton rock the size of his fist on a big boat almost as big as the pool, the water level will drop if he drops the rock in the pool. size does matter
2006-08-30 19:14:54 · answer #8 · answered by lnfrared Loaf 6 · 1⤊ 0⤋
The level stays the same, because the boat is at the bottom of the pool.
2006-08-30 19:17:14 · answer #9 · answered by Anonymous · 1⤊ 1⤋
If hes holding a rock, then hes at the bottom of the pool then right? so if he tosses it overboard it stays the same.
It all depends on the physical setting of the situation
2006-08-30 19:16:11 · answer #10 · answered by Pineapple 3 · 0⤊ 1⤋