2006-08-30 18:21:09 · 16 answers · asked by Anonymous in Science & Mathematics ➔ Chemistry
Name: beryllium
Symbol: Be
Atomic number: 4
Atomic weight: 9.012182 (3)
CAS Registry ID: 7440-41-7
Group number: 2
Group name: Alkaline earth metal
Period number: 2
Block: s-block
2006-08-30 18:27:34 · answer #1 · answered by crissyll22 4 · 1⤊ 0⤋
Instead of wasting 5 points, would it have really been that hard to check the Periodic Table yourself...?
Anyway, "Be" is the abbreviation for Beryllium, the 4th element.
2006-08-31 01:29:08 · answer #2 · answered by Angela 3 · 0⤊ 0⤋
Beryllium
2006-08-31 18:33:56 · answer #3 · answered by Anonymous · 0⤊ 0⤋
Beryllium
2006-08-31 01:24:49 · answer #4 · answered by Anonymous · 0⤊ 0⤋
What is beryllium used for? Elemental beryllium is the second lightest of all metals and is used in a wide variety of applications. It is a brittle, steel-gray metal found as a component of coal, oil, certain rock minerals, volcanic dust, and soil. In its elemental form beryllium exhibits the unique properties of being light weight and extremely stiff, giving the metal several applications in the aerospace, nuclear, and manufacturing industries. In addition, beryllium is amazingly versatile as a metal alloy where it is used in dental appliances, golf clubs, non-sparking tools, wheel chairs, and electronic gadgets. It is used for purification and processing of uranium and thorium. It is used in high-tech ceramics with military and aerospace applications.
2006-08-31 15:50:45 · answer #5 · answered by Anonymous · 1⤊ 0⤋
Beryllium.
2006-08-31 01:33:48 · answer #6 · answered by cat_in_pool 2 · 0⤊ 0⤋
Be is the abbreviation for beryllium
2006-08-31 01:26:43 · answer #7 · answered by bambi 5 · 0⤊ 0⤋
•Beryllium has a symbol Be. Beryllium is a Group 2 (IIA) element and is available in several forms including foil, lump, and powder.
2006-08-31 17:38:10 · answer #8 · answered by ♥ lani s 7 · 1⤊ 0⤋
Be for Beryllium
2006-08-31 03:29:51 · answer #9 · answered by stroby 3 · 0⤊ 0⤋
Berylium
2006-08-31 12:05:29 · answer #10 · answered by shiara_blade 6 · 0⤊ 0⤋