A circular pool (as pictured on the website you gave) that is 12 feet across and filled to a depth of 3 feet (36 inches) has a volume of pi*36*3 cubic feet = 339.3 cubic feet.
1 cubic foot = 7.481 gallons, so the pool holds 339.3*7.481 = 2538 gallons
2006-08-30 18:08:36
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answer #1
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answered by hfshaw 7
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The pool is a cylindrical shape. Volume of a cylinder = pi r^2 h r=6 ft =72 inches h=36 inches
3.14(72)^2 (36)=
585999.36 cubic inches
A gallon of water is 231 cubic inches. So the pool contains 585999.36/231 gallons or 2536.79 gallons
2006-08-30 18:08:52
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answer #2
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answered by G.V. 6
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The volume of a cylinder is calculated by π(r^2)h.
Since the diameter is 12 ft, and radius is 1/2 of diameter, the radius is 6 ft. Height is 36 inches, 12 inches is 1 foot so height is 3 feet.
pi is about 3.14159, r^2 is r*r is 36, h is 3
Volume is therefore 3.14159*36*3=339.29172
So that's about 339.3 cubic feet
1 cubic foot is about 7.48 gallons so
339.3*7.48 is about 2537.9, so we're talking about 2,538 gallons to fill that pool thing!
2006-08-30 18:15:41
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answer #3
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answered by mim 3
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First we find volume of the pool:
3 feet * pi*(radius^2). Since radius is 6 feet, we have the volume as
3*pi*6^2=3*36*pi cubic feet.
Next, we convert cubic feet to gallons using Google, which does unit conversions for you.
"3*36*pi cubic feet in gallons"
So, your answer is:
(3 * 36 * pi) * (cubic feet) = 2,538.08045 US gallons
You don't need to be a mathematician to solve this problem. You just need to know elementary-school level arithmetic, along with the conversion ratio for gallons to feet.
The previous answer refers to rectangular pools, so ignore it.
2006-08-30 18:06:48
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answer #4
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answered by czyl 1
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Need more info to solve this problem. Liquid dimensions need length, width, and height to be able to convert the space in feet into cubic dimensions such as cubic liters and then converting the liters to gallons. Good luck.
2006-08-30 18:04:19
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answer #5
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answered by tropicvibe 3
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You can't answer that question. The formula for that is Volume equals lenght times width times height and without the third dimension, you can't do the equasion.
2006-08-30 18:06:08
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answer #6
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answered by Accidentally.In.Love 3
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Right now I cannot answer that question. I need 3 demensions. width, length and depth. Without those 3 I can't tell you.
2006-08-30 17:58:17
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answer #7
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answered by Anonymous
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http://education.yahoo.com/reference/weights_and_measures/
2006-08-30 18:29:16
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answer #8
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answered by yacheckoo 4
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