plz help with math problems?

Question

i did most problems here just want to double check whoever answer are like mine gets the 10 points


===Seven people meet and shake hands with each other===

How many handshakes occur?

Using inductive reasoing write a formula for the number of handshakes if the number of people is N.


==The Fibonacci sequence 1 1 2 3 5 8 13==

What is the ninth term in the patttern

== Name two diffrent ways to continue each pattern ==

1 1 2 __

48 49 50 ___

2 4 ___

A B C ....Z ___

D E F ____

A Z B ____

Answer 1

21 handshakes. The seven people are A,B,C,D,E,F, and G. If A shakes 6 hands, B shakes 5 hands, C shakes 4 hands, D shakes 3 hands, E shakes 2 hands, F shakes 1 hand. By then, everyone has shook G's hand.

1 1 2 3 5 8 13 21 34
to get the next number add the previous.
0 to 1 to get 1
1 to 1 to get 2
1 to 2 to get 3
2 to 3 to get 5
3 to 5 to get 8
5 to 8 to get 13
8 to 13 to get 21
13 to 21 to get 34

problems:
1. 2 or 3
2. 51 or 58
3. 6 or 8
4. yx or ab
5. g or d
6. y or z

Answer 2

Just guessing...been awhile since I did this kinda stuff....

21 handshakes
Not sure of the formula, but the first person shakes hands with the 6 others, the next person shakes hands with 5, cuz he already shook with the first one and can't shake his own, then the next person shakes with 4 people, the next person shakes with 3 and so on...

Fibonacci=34

patterns=
#1= 2 or 3
#2= 51 or 58
#3= 6 or 8
#4= A or a
#5= G or H
#6= Z or Y

Answer 3

Let me try, ok, i'll just wake up my brain cells here...

Question 1) N=number of people; 7 people
x=number of hands used for shaking ; if x=6 (each person would would be shaking hands with the other 6)
Y-number of handshakes
Hence, it will be Y=xN
=6(7)
=42
Question 2) 34
Question 3.a) 1 1 2 could be 3 use the Fibonacci sequence or could be 3 1x1=1 , 1x2=2, 1x3=3
3.b) 48 49 50 could be 51 add just 1
long method: 48/2x2+1=49, 49/2x2+1=49, 50/2x2+1=51 and so on....
3.c) 2 4 could be 6 just add 2 or 16 multiply the digit by itself ( 2x2=4, 4x4=16...)
3.d) A B C...Z could be AA, BB or AZ, AY, AX
3.e) DEF could be G or FI (use the vowels cA dE fI gO hU)
3.f ) AZB could be Y or BZ

Ok, study your math now...Good luck!

Answer 4

(n-i)+(n-2)....
6+5+4+3+2+1=21,
nth term
1 1 2 3 5 8 13 21

1 1 2 4 10 50 550
48 49 50 51 52

Answer 5

handshakes-if everyone shakes hands with everyone else once-21 handshakes (the formula is n((n-1)/2))

1 1 2 3 5 8 13 21 34

1 1 2 2 3 3... or 1 1 2 3 5 8...
48 49 50 51... or 48 49 50 49 52 49 53 49...
2 4 6 8 ... or 2 4 8 16 32....
ABC...ZABCD or ABC...ZZYX...
DEFGHI... or DEFDEFDEF....
AZBZCZ.... or AZBYCX...

Answer 6

ok. properly in accordance to the orders of operation- you will possibly desire to do exponents first. So 3 to the 2nd ability is 9 and 3 to the third ability is 27. you have now 9+2 x 27. next, you will possibly desire to do multiplication. So 2 x 27 is fifty 4. you at the instant are left with 9+fifty 4 that's sixty 3!

Answer 7

1/
6+ 5+4+3+2+1
(n-1)+(n-2)+....+1

2/
1,1,2,3,5,8,13,21,34
3/
2 or 3
51 or 48
6 or 8
Y or A
G or D
Y or C

Answer 8

a shakes hand with b,c,d,e,f,g = 6 hand shakes
b shakes hand with c,d,e,f,g (a already counted) = 5 hand shakes
c shakes hand with d,e,f,g (a, b already counted) = 4
d shakes hand with e,f,g = 3
e shakes hand with f,g = 2
f shakes hand with g = 1
g shakes hand with (a,b,c,d,e,f already counted) = 0
total = 6+5+4+3+2+1 = 21 hand shakes

or

hand shakes = n/2 * (n-1)

Answer 9

42 handshakes

Answer 10

there are 21 shakehands