Help with simple math problems?

Question

shows steps plz

17, 23, 29, 35, 41

1.01. 1.001. 1.0001

12.14.18.24.32

2 - 4 8 -16 32

1, 2, 4, 7 , 11 , 16

32, 48 , 56 , 60, 62, 63

I would if i knew how to!! i need help

Answer 1

first of all, you have a really nice avatar !! :_)
(looks just like mine except the backdrop.)

1) +6
2) 1/10
3) +2, +4, +6, +8
4) -4, +8, -24, +48

ok, enuf

Answer 2

I'm assuming you want the next number in the sequence?

17, 23, 29, 35, 41. 47 (you are adding 6 each time)

1.01 1.001 1.0001 1.0001 (you are moving the "1" to the right of the decimal point one place over)

12 14 18 24 32 42 (difference between 12 and 14 is *2*, difference between 14 and 18 is *4*, difference between 18 and 24 is *6* , the difference between 24 and 32 is *8*, (note the pattern of differences 2,4,6,8) so the next difference, between 32 and the next number should be *10* (so the next number in the sequence is 42)

2-4 8-16 32-64 (2 doubled is 4, 8 doubled is 16, so 32 doubled is 64).

1,2,4,7,11,16, 22 The difference between 1 and 2 is *1*, the difference between 2 and 4 is *2*, the difference between 4 and 7 is *3* (notice the pattern??)

32, 48, 56, 60, 62, 63, 63 1/2 The difference between 32 and 48 is *16*, the difference between 48 and 56 is *8*, the difference between 56 and 60 is *4*, the difference between 60 and 62 is *2*, the difference between 62 and 63 is *1*. See how the differences are halved each time (16,8,4,2,1), So the difference between 63 and the next number in the series should be 1/2 of 1 or 1/2. Theref ore the next number in the series should be 63 1/2.

Answer 3

17, 23, 29, 35, 41, 47 Here add 6 to the previous number

1.01 1.001 1.0001 1.00001 Here terms are coming by {1+(.1/10)}

12.14.18.24.32, 42 add intervals of 2. So add 2 (to 12), then 4 (to 14), then 6(to18), similarly add 10 to 32= 42

2 - 4 8 -16 32 -64 multiply previous number by negative 2, so 32X-2= -64

1, 2, 4, 7 , 11 , 16, 22 Add 1, 2 3 4 .... to each result of pvs no, e.g. 1+1=2 2+2=4 4+3=7 7+4=11 11+5=16 & 16+6=22

32, 48 , 56 , 60, 62, 63 ----> Add to each pvs result, consecutively diminishing powers of 2^4, e.g. 32+2^4=48 48+2^3=56 56=2^2=60 60+2^1=62 62+2^0=63 63+2^-1= 63.5

Answer 4

17, 23, 29, 35, 41 ----> Add 6 to the previous number

12.14.18.24.32 ----> add intervals of 2. So add 2 (to 12), then 4 (to 14), then 6, then 8

2 - 4 8 -16 32 -----> multiply previous number by negative 2

1, 2, 4, 7 , 11 , 16 ---> start by adding 1 (to 1 to get 2), then add 2 (to 2 to get 4), then 3, then 4, then 5, etc, etc.

32, 48 , 56 , 60, 62, 63 ----> add 16 (to 32 to get 48) then 8 then 4 then 2 then 1.

Not sure about the second one (1.01, 1.001, etc).

Answer 5

I would assume you tried solving it yourself first. Otherwise, you would not benefit from doing your homework.

Anyway, the answer to the second question is 1.00001

The logic is to add another 0 in between the two 1's.

Answer 6

What am I going to do with those numbers? give more information.

Answer 7

For the last time,...you Damn kidz need to do yer own homework!!

Answer 8

do your own homework!!!