-2 - (-2) - I-2I(2) I am working with absolute values can anyone help me?

Question

Is there a site where I can check my answers. This is my first year taking algebra.

Answer 1

-2-(-2)-l-2l(2)l

-2+2-l2l(2)l

-2+2-(4)

0-4

-4

First, the negatives cancel because 2 minus negative 2 equals 2+2. so, negative plus negative (2-(-2)) is positive (2+2). Anything in absolute value is positive so.. l-2l=l2l or 2. Then you want to do the order of operations, PEMDAS: parenthases, exponents, multiply, divide, add, subtract. We can skip down to multiply....and you multiply the 2's. l2l(2)l to get 4...they are both in absolute value....they are both positive. Next, we add, and they cancel each other: -2+2=0. If you look at a number line, and move two to the right of negative two, it's 0. Therefore, if ypu move four to the left of zero, it's negative again, which makes -4. So...that's the answer....-4.

Answer 2

Well, you just have to google "homework help" to find a whole lot of useful websites. As for your question, remember the following tips:

absolute numbers mean real value, that means all numbers are to be converted into positives. so for the l-2l in the above question, you will have to convert it to 2.

therefore:

-2 - (-2) - I-2I(2) becomes

-2+2-(2)(2) becomes

-2+2-4 becomes

-4

hope that helped.

Answer 3

Ok. The X trigit value of your first integer is almalgamated, so you need to reverse the hypoid to X(9-5*4^9))1 and transverse the next to match the other integer, so it of course is "Q". Now, if we add the free radicals it changes to 7(2*x^8))-2*____8(2*65)45M<4*I>))

So when you are done, you wind up with the answer of P2-1. Simple. Any questions, just ask.

Answer 4

dont kno any sites, but I believe the answer to that one is 16?

Answer 5

meow

Answer 6

google math calculator you will get what you want'