solve for x
2x(5x-4)=15x(4-9x)
2006-08-30 16:01:55 · 13 answers · asked by the_swig_12 1 in Science & Mathematics ➔ Mathematics
can you solve it and step by step how its done?
2006-08-30 16:05:10 · update #1
2x(5x-4) = 15x(4-9x)
10x^2 - 8x = 60x - 135x^2
145x^2 - 68x = 0
Factorising it,
x(145x - 68) = 0
x=0 and x = 68/145
2006-08-30 16:09:21 · answer #1 · answered by Nirmal87 2 · 2⤊ 0⤋
This is old..
Well, here it is:
2x(5x-4)=15x(4-9x) Distribute possibly??
10x²-8x=60x-135x² Let's move it to one side, shall we?
10x²-8x-60x+135x²=0 Simplify!
145x²-68x=0 Factorize x out.
x(145x-68)=0 We're at the end.
x=0, 68/145
68
¯¯ ~~~68/145
145
2006-08-30 23:48:34 · answer #2 · answered by darktorcher 2 · 0⤊ 0⤋
x=0
2006-08-30 23:06:57 · answer #3 · answered by N 2 · 0⤊ 1⤋
2x(5x - 4) = 15x(4 - 9x)
10x^2 - 8x = 60x - 135x^2
145x^2 - 68x = 0
x(145x - 68) = 0
145x - 68 = 0
145x = 68
x = (68/145)
ANS : x = 0 or (68/145)
2006-08-30 23:12:55 · answer #4 · answered by Sherman81 6 · 0⤊ 0⤋
10x^2 - 8x = 60x - 135x^2
145x^2 - 68x = 0
x(145x-68)=0
x = 0 or 68/145
2006-08-30 23:15:10 · answer #5 · answered by Anonymous · 0⤊ 0⤋
2x*5x-2x*4=15x*4-15x*9x
then go from there. have fun
2006-08-30 23:07:05 · answer #6 · answered by Tawn 2 · 0⤊ 0⤋
142xsquare-68x=0
2006-08-30 23:06:25 · answer #7 · answered by melai 1 · 0⤊ 0⤋
Thanks dude - now you got me pounding my head to remember how to do these, arghh (quadratic formulaes, right?). Don't make me have to break out my math books...........
I got as far as: 145x^2 - 60x -4 = 0
2006-08-30 23:09:05 · answer #8 · answered by dokter_fill 1 · 0⤊ 1⤋
10x^2-8x=60x-135x^2
-68x=-145x^2
145x^2-68x=0
im pretty sure hope it helps
2006-08-30 23:10:58 · answer #9 · answered by sexiisoccerboy 2 · 0⤊ 0⤋
9 lol
2006-08-30 23:07:29 · answer #10 · answered by skooba71 1 · 0⤊ 2⤋