y = (x-6)^2 - 1
to solve for the x-int, do i need to factor out the (x-6)?
to solve for the y-int, do i plug whatever "x" is into the equation?
thanks for the help.
2006-08-30 15:03:01 · 11 answers · asked by shih rips 6 in Science & Mathematics ➔ Mathematics
To find the x-intercept you need to set y to 0:
y = (x - 6)^2 - 1
0 = (x - 6)^2 - 1
0 = x^2 - 12x + 36 - 1
0 = x^2 - 12x + 35
0 = (x - 7)(x - 5)
So then x must be either 7 or 5 when y = 0.
So the x-intercepts are 7 and 5.
For the y-intercept, you need to set x to 0.
y = (x - 6)^2 - 1
y = (0 - 6)^2 - 1
y = (-6)^2 -1
y = 36 - 1
y = 35
So then y must be 35 when x is 0.
So the y-intercept is 35.
Good luck!
=)
2006-08-30 15:06:56 · answer #1 · answered by Jess 2 · 2⤊ 0⤋
To solve for the x intercept, set y to zero and solve for x.
(x-6)^2 - 1 = 0
(x-6)^2 = 1
(x-6) = +/-1
so x = 7 and x = 5 are the x intercepts.
To solve for the y intercept, set x to zero and solve for y
y = (-6)^2 - 1 = 35
That means the function intercepts the y axis when y = 35.
2006-08-30 22:16:44 · answer #2 · answered by just♪wondering 7 · 0⤊ 0⤋
To solve for the y-int, plug in 0 for x and solve (35)
To solve for the x-int, plug in 0 for y and solve (5 and 7)
2006-08-30 22:11:38 · answer #3 · answered by Anonymous · 0⤊ 0⤋
To find x-int, set y = 0 and solve for x.
To find y-int, set x = 0 and solve for y.
So, y-int is (0, -1)
x-int is solution of x^2 - 12x +35, or (x-5)(x-7),
which would give two answers, (5, 0) and (7, 0).
2006-08-30 22:09:43 · answer #4 · answered by AmyAKy 2 · 0⤊ 0⤋
For the x-intercept you plug in 0 for y and for the y-intercept you plug in 0 for x.
x-int: 0=(x-6)^2-1 etc.
good luck
2006-08-30 22:07:24 · answer #5 · answered by Anonymous · 0⤊ 0⤋
The y intercept is the constant. You can either expand the equation to find it or simply plug 0 in for x. You will get 35.
To find the x intercept you set y equal to 0 and solve.
2006-08-30 22:04:48 · answer #6 · answered by Elim 5 · 0⤊ 1⤋
to solve equations like this is a matter of substitution. start in if x=o, y would be ?, then if x=1, y=?, then x=2, y=?... and so on. then you will know the intercepts.
2006-08-30 22:17:37 · answer #7 · answered by Daniel Ira L. Cuevas 2 · 0⤊ 0⤋
y-intercept: Set x = 0
y = (0-6)^2 - 1
y = (-6)^2 - 1
y = 36 - 1
y = 35
y-intercept is (0,35)
x-intercept: Set y = 0
0 = (x-6)^2 - 1
Add 1 to each side
1 = (x-6)^2
Take the square root of each side
+/- sqrt(1) = x-6
+/- 1 = x-6
1 = x-6 or -1 = x-6
x = 7 or x = 5
x-intercepts: (7,0) and (5,0)
2006-08-30 22:07:15 · answer #8 · answered by MsMath 7 · 0⤊ 0⤋
substitute 0 for x to find the y intercept and 0 for y to find the x int.
very simple or u can use the calculator and graph it
2006-08-30 22:08:23 · answer #9 · answered by I Got a St. Patty's Baby! 4 · 0⤊ 0⤋
graphing calc.
or put 0 in for y and solve that way.
2006-08-30 22:05:15 · answer #10 · answered by rogue chedder 4 · 0⤊ 0⤋