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(49,2) and (79,4) I don't know how how to put them in an equation? U know an equation that can be graphed or someting like that? PLEASE help?

2006-08-30 14:54:14 · 9 answers · asked by ChrisIsMyName 1 in Science & Mathematics Mathematics

9 answers

m = (4-2)/(79-49) = 2/30 = 1/15 = slope
y = (1/15)x + b
Use either one of your points and solve for b.
x = 49 and y = 2
2 = (1/15)(49) + b
2 = 49/15 + b
2 - 49/15 = b
30/15 - 49/15 = b
-19/15 = b
Answer: y = (1/15)x - 19/15

2006-08-30 14:58:49 · answer #1 · answered by MsMath 7 · 0 0

The equation of a Straight Line is given by,

y = mx + c

where

m is the gradient
c is the y-intercept

Finding m,

m = (4 - 2)/(79 - 49) = 2 / 30 = 1/15

The equation is therefore,

y = (1/15) x + c

Substitute x = 49 and y = 2 to find c,

2 = (1/15) (49) + c

c = 2 - 49/15

c = (30 - 49)/15

c = - 19/15

Therefore,

y = (1/15) x - 19/15

15y = x - 19

2006-08-30 22:52:06 · answer #2 · answered by ideaquest 7 · 0 0

There's an infinite number of equations whose graphs go through 2 given points, but the simplest is a straight line. Its slope is change in y over change in x, 2/30 in this case. Using point-slope form and the first point, y-2 = (1/15)(x-49). If your teacher insists on slope-intercept form, solve it for y and clean up the right side:

y - 2 = x/15 - 49/15
y = x/15 - 49/15 + 2
y = x/15 - 49/15 + 30/15
y = x/15 - 19/15.

2006-08-30 15:12:39 · answer #3 · answered by Philo 7 · 0 0

If you have two points, you can write the equation of a line that goes between them, but there are numerous other possibilities.

The line that goes through these two points would have a slope of 1/15, based on the change in y over the change in x. So a possible equation for these two points, would be

y-2=(1/15)(x-49) (point-slope form)

y = x/15-19/15 (slope-intercept form)

2006-08-30 15:08:34 · answer #4 · answered by just♪wondering 7 · 0 0

use Excel. first row 49 2; second row 79 4. Select these four and draw a chart. and it will show a line. and then you right click the line "edit trendline". check "display equation on chart". the equation is right there. y=0.0667x-1.2667. this is just an example. on Excel, you can do more complicate equations.

Secondly, for this one, you can use this technic,

(y-2)/(4-2)=(x-49)/(79-49)
-->(y-2)=(x-49)*(4-2)/(79-49)
-->y=(1/15)x-49/15+2

2006-08-30 15:11:42 · answer #5 · answered by Anonymous · 0 0

(49,2) and (79,4)

m = (4 - 2)/(79 - 49)
m = 2/30
m = (1/15)

(49,2), m = (1/15)
2 = (1/15)(49) + b
2 = (49/15) + b
30 = 49 + 15b
-19 = 15b
b = (-19/15)

ANS : y = (1/15)x - (19/15)

2006-08-30 16:27:25 · answer #6 · answered by Sherman81 6 · 0 0

any #'s can be put into a equation what are you trying to prove with your equation 49 - 2 = 47 or something completely different what kind of math are you doing anything that is subject to math can be graphed

2006-08-30 15:03:09 · answer #7 · answered by Anonymous · 0 0

Those are two points each point is an x and y value. I am sure that your teacher wants you to write the equation for a line which travels through both of those points.

2006-08-30 14:57:43 · answer #8 · answered by rscanner 6 · 0 0

dk 4 naw

2006-08-30 15:16:04 · answer #9 · answered by ? 3 · 0 0

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