how do i factor this equation? so far i have (x ) (x ). what do i do next to solve for the inner #'s? thanks for the help.
2006-08-30 13:18:15 · 10 answers · asked by shih rips 6 in Science & Mathematics ➔ Mathematics
x^2 - x = 30
Subtract 30 from both sides:
-30 -30
That gives you:
x^2 - x - 30 =0
Now you can factor:
(x-6)(x+5)
2006-08-30 13:20:43 · answer #1 · answered by Anonymous · 2⤊ 1⤋
x^2 - x - 30
= x^2 - x + 1/4 - 121/4
= (x - 1/2)^2 - (11^2)^2
= (x -1/2 +11/2) (x - 1/2 + 11/2)
( by applying the formula a^2 - b^2 = (a+b)(a-b))
= (x+5)(x-6), which is the required factorization.
So, x^2 - x = 30, gives:
x^2 - x - 30 = 0
Or, (x+5)(x-6) = 0
Or, x = -5, 6.
2006-08-31 06:13:43 · answer #2 · answered by K Sengupta 4 · 0⤊ 0⤋
first subtract 30 from both sides to get x^2-x-30 then you find two factors of -30 that add up to -1. The answer is (x-6)(x+5)
2006-08-30 13:22:03 · answer #3 · answered by jman 2 · 0⤊ 1⤋
x^2 - x = 30 (Subtract 30 from both sides)
x^2 - x - 30 = 0 (Factor from here)
(x - 6)(x + 5) = 0
x = 6 or x = -5
QED
2006-08-30 14:20:45 · answer #4 · answered by CSUFGrad2006 5 · 0⤊ 0⤋
x^2 - x = 30
x^2 - x - 30 = 0
(x - 6)(x + 5) = 0
Note that -6 x 5 = -30 and -6x + 5x = -x
2006-08-30 13:49:50 · answer #5 · answered by ideaquest 7 · 0⤊ 0⤋
x^2 - x = 30
x^2 - x - 30 = 0
(x - 6)(x + 5) = 0
x = 6 or -5
2006-08-30 16:41:59 · answer #6 · answered by Sherman81 6 · 0⤊ 0⤋
x^2-x=30
x^2-x-30=0
(x-6)(x+5)=0
x-6=0 x+5=0
x=6 x= -5
2006-08-30 13:26:12 · answer #7 · answered by Anonymous · 0⤊ 0⤋
sTEP 1: X^2- X-30=0
STEP2 : X^2-6X+5X-30=0
STEP 3: (X-6)(X+5)
STEP 4: X=6,-5
2006-08-30 13:55:14 · answer #8 · answered by navigator 1 · 0⤊ 0⤋
This is sooo cake!!! Use the quadratic equation!!! Too bad i cant remember it sorry, but im sure u can find it some place!!!
2006-08-30 13:21:05 · answer #9 · answered by Anonymous · 0⤊ 2⤋
Algebraically speaking, .TheChinaDoll. has your best answer.
2006-08-30 13:40:50 · answer #10 · answered by butch 5 · 0⤊ 0⤋