AC=3x-1,BC=12-x;Line AB?

Question

Find the value of x and the measure of the indicated segment.

Answer 1

Assuming that A,B,and C are collinear (on the same line), then AB = AC + BC,

so AB = 3x-1+12-x

ANSWER : AB =2x+11

Answer 2

OK first off, since AC=3x-1, you can either take half of that, or double 12-x to find x because if B is a point on the same line between A and C then AB=BC and AC=AB+BC or 2BC so you get
3x-1=24-x2
5x=25
x=5
therefor AC=14 and AB=7

Answer 3

you could the two purely remedy it by ability of looking the slope then plugging in values, or in basic terms be sure its genuine. Heres the two strategies. First approach : locate slope m = -a million - 2 / (-a million - 11) m = -3/ -12 m = 3/12 m = a million/4 as a result we've the equation y = a million/4x + b Plugging in any factor will artwork, so we %. -a million -a million for simplicities sake. as a result -a million = a million/4(-a million) + b -a million = -a million/4 + b -a million + a million/4 = b -4/4 + a million/4 = b -5/4 = b The equation is y = a million/4x - 5/4 Bringing into widely used type yields x-4y = 3 approach 2 : examine the factors utilising LS RS ( Left section top section ) We plug interior the factors to coach the left section = rightside LS RS 11 - 4(2) 3 3 3 LS = RS as a result the factor is on the line

Answer 4

AC=3x-1, BC=12-x
AC=2x-1, BC=12
AC=2x-1+1 BC=12+1
AC=2x, BC=13

x=6.5

Eek. I think I may be misinterpreting this.

Answer 5

AC = 3x - 1
BC = 12 - x
AB = AC + BC

AB = (3x - 1) + (12 - x)
AB = 3x - 1 + 12 - x
AB = 2x + 11