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Calculus 3 Vectors: The Cross Product Section

2006-08-30 13:10:46 · 6 answers · asked by jrosales9@sbcglobal.net 1 in Science & Mathematics Mathematics

6 answers

HOMEWORK!!!

Take the cross product of these two vectors. This gives a vector normal to both. Now divide by it's length to get a unit vector with that property. Another is obtained by taking the negative of that one.

2006-08-30 13:17:40 · answer #1 · answered by mathematician 7 · 4 1

take the cross product of those two vectors, that gives you an orthongal vector to both of them, to make it a unit vector, divide by its norm.
the cross product of < 1, -1, 1> and <0,4,4> is: <-8,-4,4>, the unit vector therefore is:
1/√96<-8,-4,4>
the second unit vector would be the negative of the first.
-1/√96<-8,-4,4>

2006-08-30 13:20:01 · answer #2 · answered by Anonymous · 1 0

Take the cross product of the 2 vectors to get a vector
orthogonal to both.
I got <-8, -4, 4>. Now normalise it by dividing by its length.
This gives <-8, -4, 4>/sqrt(96).
Another unit vector can be obtained by taking
the negative of this one.

2006-08-30 13:26:06 · answer #3 · answered by steiner1745 7 · 1 0

Cross product:

= [1, -1, 1] . [0, 4 , 4]
= [ -8 , -4 , 4]
= 4 [ -2, -1, 1]

Magnitude of cross product
= sq rt of { (-8)² + (-4)² + 4² }
= sq rt of 96

Therefore,
One of the unit vectors is (4/ sqrt 96) [ -2, -1 ,1]
i.e. ( [ -2, -1 ,1] / sqrt 6 )

And the other vector is the negative,
i.e. ( [ 2, 1, -1] / sqrt 6 )

2006-08-30 13:32:54 · answer #4 · answered by canzoni 3 · 2 0

Last time I checked, I don't have any homework today.

2006-08-30 13:16:07 · answer #6 · answered by loveblue 5 · 0 4

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