I am being offered Hasselbeck and Moss for Palmer and Holt. What do you think abut this trade?
2006-08-30 12:15:49 · 7 answers · asked by Anonymous in Sports ➔ Fantasy Sports
Randy Moss by the way, but I think I'm leaning towards not making this trade.
2006-08-30 12:53:53 · update #1
don't whichever moss, santana or randy, doesn't matter. hasselback is good but not worth it in this one. palmer, if he stays healthy will be great. and holt is the only real solid receiver the rams have as Curtis and Bruce are up for grabs. keep them.
2006-08-30 12:46:06 · answer #1 · answered by Anonymous · 0⤊ 0⤋
It's a really interesting deal... I would keep Hasselbeck and Moss if I were you because Moss is going to get his old numbers he had in Minnesota if he stays healthy and Brooks can get him the ball like he did in week 3 of the preseason.
Also, Holt is in a new run-oriented offense. Therefore, he is not going to get nearly as many yards as he did is Martz' Greatest Show on Turf, however, will still get good stats. Palmer is a top 5 QB, although I wouldn't trade Hasselbeck and Moss for Palmer and Holt.
2006-08-30 21:53:19 · answer #2 · answered by Anonymous · 0⤊ 0⤋
Palmer is better than Hasselbeck, Holt is better than Moss. No reason to make that trade.
2006-08-30 20:12:54 · answer #3 · answered by numbnuts 3 · 0⤊ 0⤋
Not so good, in my opinion. But, I believe, Palmer will attain demi-god status this season... besides Holt has a better QB throwing to him.
2006-08-30 19:21:07 · answer #4 · answered by Savage 3 · 0⤊ 0⤋
decline it. moss wasn't as productive last yr. and he has 2 deal with a new qb and a rb who will carry more. palmer also was phenomenal in his first game back.
2006-08-30 21:55:00 · answer #5 · answered by parasdaman1 2 · 0⤊ 0⤋
Even though I am a Seahawks fan, I would not give up Carson Palmer.
2006-08-30 19:20:29 · answer #6 · answered by ADF 5 · 0⤊ 0⤋
stay put.........moss may not have anyone to get him the ball....brooks is hard to read....never consistant.......Palmer and holt by a mile
2006-08-30 20:14:18 · answer #7 · answered by steve f 2 · 0⤊ 0⤋