If a ball travels 149.6 ft/ per sec on average then how long does it take the ball to reach from the pitcher's mound to the home plate in minute maid park?(The distance between the home plate and pitcher's mound is 60 feet and 6 inches.)
2006-08-30 12:13:27 · 14 answers · asked by lisa 1 in Education & Reference ➔ Homework Help
60.5/149.6 seconds
=0.4 seconds
2006-08-30 12:19:44 · answer #1 · answered by odu83 7 · 0⤊ 0⤋
By now this question is completely confusing. Some people are saying to divide the speed by the distance and coming up with 2.4727 and some are dividing the distance by the speed and coming up with .408.
Let's look at it this way, in one second the ball can travel 149.6 feet. Since it only has to go 60.5 feet (.5 feet = 6 inches) then it will take less than one second to get there. My money is on the group that said .408 seconds.
2006-08-30 12:47:44 · answer #2 · answered by Anonymous · 0⤊ 0⤋
Think about it this way, if the ball travels 149.6 ft/sec then after 1 second the ball will have traveled exactly 149.6 ft right? (yes it is)
So 60ft and 6 inches or 60.5 feet being less of a distance than 149.6 feet one would have to conclude that it would take less than 1 second to travel that distance correct? (of course)
So you take the distance the ball traveled and divide it by its speed to find out how long it took to get there. Make sense? (It should)
So now its a simple matter of plugging the numbers into your calculator.
60.5(ft) is your distance traveled, 149.6(ft/sec) is your speed and 60.5/149.6 which equates to approximately 0.404(sec) is your time.
The official equation is S = D/T or Speed = Distance/Time which by multipling both sides by T we get S*T = D then dividing both sides by S we get T = D/S or Time = Distance/Speed. Which is what we discovered above, you now have the equations to find S, D, or T if need be.
2006-08-30 13:00:40 · answer #3 · answered by Justaguyinaplace 4 · 1⤊ 0⤋
First put your factors in equal terms: you know the feet per second the ball can travel, so convert the distance being traveled to feet. That would be 60.5.
The time it would take the ball to travel any distance is equivalent to how many times the distance being traveled can be divided by the ball's average speed: 60.5 / 149.6 = .4044...
Your answer is .40 seconds.
2006-08-30 12:25:01 · answer #4 · answered by nyboxers73 3 · 0⤊ 0⤋
149.6 feet * 12 gets 1795.2 inches.
60 feet 6 inches is 726 inches
1795.2/762 gets 2.3559etc etc etc[lots of decimal places] to 4 significant digits ...
2.356 seconds.
oh wait switch those numbers around yeah that's the problem
now you can do your homework....
2006-08-30 12:24:45 · answer #5 · answered by quntmphys238 6 · 0⤊ 0⤋
2.472727272727272727272727272727273
divide the distance of the ball by the length of the pithcher's mound to home plate
149.6 by 60.5 (60 ft and a half)=
2.472727272727272727272727272727273
2006-08-30 12:28:10 · answer #6 · answered by Procrastination Kills. 3 · 0⤊ 0⤋
60 feet and 6 inches = 60.5 feet (cause 6 inches is 1/2 foot)
(60.5 feet) / (149.6) = .4044117 seconds
2006-08-30 12:23:30 · answer #7 · answered by kchivers-carter@sbcglobal.net 2 · 0⤊ 0⤋
2.472727
you convert 60ft & 6 inches and149.6ft to inches (149.6 * 12=1795.2) and 60ft & 6 inches (60 * 12= 720 + 6)
and then you divide it..
1795.2/726=2.472727
2006-08-30 12:28:31 · answer #8 · answered by Anonymous · 0⤊ 0⤋
Here is how I did it:
149.6 = 1
60.5 = x
you cross-multiply (60.5 times 1)(149.6 times x)
and you get this:
60.5 = 149.6x
now, divide 149.6 from both sides
60.5 = 149.6x
149.6 149.6
and you should get this:
0.404411764 = x
2006-08-30 13:06:01 · answer #9 · answered by trainboy765 4 · 0⤊ 0⤋
little more than 1/2 a second
2006-08-30 12:19:33 · answer #10 · answered by koolguy402003 1 · 0⤊ 0⤋