2006-08-30 11:42:43 · 4 answers · asked by Desert Storm 1 in Science & Mathematics ➔ Mathematics
(x^2 - 5x)^2 - 8(x^2 - 5x) - 84
((x^2 - 5x) - 14)((x^2 - 5x) + 6)
(x^2 - 5x - 14)(x^2 - 5x + 6)
(x - 7)(x + 2)(x - 3)(x - 2)
Just think of the problem like
x^2 - 8x - 84
which factores to (x - 14)(x + 6)
which "x" = x^2 - 5x
2006-08-30 17:00:44 · answer #1 · answered by Sherman81 6 · 0⤊ 0⤋
Can you please write the expression in a legible way.
I am guessing you mean this: (x^2 - 5x)^2 - 8(x^2 - 6x) - 84
And if so, the factor result is: - 10 x^3 + 17 x^2 + x^4 + 48 x - 84
2006-08-30 18:48:13 · answer #2 · answered by Pedromdrp 2 · 0⤊ 0⤋
I got x^4-10x^3+17x^2+48x-84.
Here is how:
I like to write out what I am squaring even though most find it unnecessary (because I am great at stupid mistakes).
(x^2-5x)(x^2-5x)-8(x^2-5x)-84 "foil" the first term and distribute the 8
x^4-5x^3-5x^3+25x^2-8x^2+48x-84 add like terms
x^4-10x^3+17x^2+48x-84
Yay, all done!
2006-08-30 19:00:21 · answer #3 · answered by firefly 3 · 0⤊ 0⤋
im not eineshtien
2006-08-30 18:51:55 · answer #4 · answered by Anonymous · 0⤊ 0⤋