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18d(squared) + 19d - 12

9y(to the fourth) + 8y(squared) - 1

2006-08-30 10:34:49 · 8 answers · asked by allstarbri22 2 in Science & Mathematics Mathematics

8 answers

The first one is (2d + 3) (9d - 4), while the second expression is (3y - 1) (3y + 1) (y^2 + 1)

2006-08-30 10:39:11 · answer #1 · answered by Pedromdrp 2 · 1 0

use the FOIL method. first x first, outer x outer, inner x innner, last x last. find out the factors of the first term and last term, make sure your +/- is correct, and combine the middle terms. You reverse this process to find factors involved in creating a sum. Factors of 18 are 1 18, 2 9, 3 6. Factors of 12 are 1 12, 2 6, and 3 4. + & - in sum mean + & - in factors. and the only combination of factors to yield + 19 are +27 and -6, so you get (2d + 3)(9d - 4). Remultiply to check your answer. You need to recognize the second one as the product of a perfect square and a third factor: (3y+1)(3y-1) = 9y^2 - 1 (9y^2-1)(y^2+1) = 9y^4+8y^2 - 1. Hope this helps....

2006-08-30 10:54:18 · answer #2 · answered by dbs1226 3 · 0 0

18d^2 + 19d - 12
(9d - 4) (2d + 3)
check your answer by FOILing(distributing) it.

9y^4 + 8y^2 - 1
(9y^2 - 1) ( y^2 + 1)
(9y^2 - 1) is a difference of 2 squares, so it can be factored farther.
(3y - 1)(3y + 1) (y^2 + 1)

2006-08-30 10:41:14 · answer #3 · answered by smartee 4 · 0 0

18d^2 + 19d -12
=(9d + 4)(2d - 3)

is fully factored.

9y^4 + 8y^2 - 1
= (9y^2 - 1)(y^2 + 1)
=(3y - 1)(3y + 1)(y^2 + 1)

is fully factored.

2006-08-30 10:51:52 · answer #4 · answered by Paul W 2 · 0 0

18d^2 + 19d - 12 = (2d + 3)(9d - 4)
9y^4 + 8y^2 - 1 = (9y^2 - 1)(y^2 + 1) = (3y - 1)(3y + 1)(y^2 + 1)

2006-08-30 17:09:26 · answer #5 · answered by Sherman81 6 · 0 0

You should use D(for delta) D=b^2-4*a*c where it's
a*x^2+b*x+c where x is unknown
that gives us D=1225
you have x1= (-b+sqrt(D))/2*a or x2=( (-b-sqrt(D))/2*a)
x1=4/9 or x2=-1,5

9*y^4 + 8*y^2 -1 =0 //substitute y^2=x //x must be positive
9*x^2 +8*x-1 = 0
D=64+36 = 100
sqrt(D)=10
x1= 1/9 or x2=-1 // x2 is not positive
y^2=1/9 => y = 1/3

2006-08-30 10:48:03 · answer #6 · answered by Jakub J 2 · 0 0

Hm... i don't think of there are any conceivable numbers to plug on your _ . I advise you take advantage of the Quadratic formula. also, because that's -a million, your splitted equations must be like this (#x+_) (#x-_) i'll attempt that could help you remedy this problem in the advise time. ok, the recommendations are: (I actual have not double examine this, yet see if it matches your answer). -2+?37 / 33 (-2 plus sq. root of 37 divided by using 33) or -2-?37 / 33 (-2 subtract sq. root of 37 divided by using 33)

2016-11-23 15:00:00 · answer #7 · answered by ? 4 · 0 0

Call your math teacher

2006-08-30 10:40:06 · answer #8 · answered by Anonymous · 0 0

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