2006-08-30 09:32:04 · 9 answers · asked by iluvhipos 3 in Science & Mathematics ➔ Mathematics
Here is your correct answer;
Well dear first you need to simplify ' Sin B '.
▪ sin (B) = 5 ((√2)) /( 5 (√3))
now you can remover ' 5 ' in this Fraction, the result is ;
▪ sin (B) = (√2) /(√3)
now we have;its csc(x) formula dear . csc(x) = 1/(sin(x))
▪ csc(B) = 1/(sin (B))
▪ csc(B) = 1/ (√2) /(√3)
▪ csc(B) = (1/1)/ (√2) /(√3)
▪ csc(B) = (1* √3) / (1 *√2)
▪ csc(B) = ( √3) / (√2) = (√3/2) = √1.5 = 1.22
Good Luck. Hope i could help you
2006-08-30 11:12:40 · answer #1 · answered by sweetie 5 · 1⤊ 0⤋
The answer is sqrt (3/2). Â Â Â (see below for details)
csc B = 1 / sin B
Therefore, csc B = 1 / (5sqrt2 / 5sqrt3)
= 5sqrt3 / 5sqrt2 Â Â Â (inverted the fraction 5sqrt2 / 5sqrt3 in order to get rid of the fraction in the denominator)
= sqrt3 / sqrt2 Â Â Â (cancelled out the fives)
= sqrt (3/2)
which is approximately 1.22
2006-08-30 17:29:41 · answer #2 · answered by lcamccandlj 3 · 0⤊ 0⤋
csc B=1/sin B=(5sprt3/5sqrt2)
2006-08-30 16:35:52 · answer #3 · answered by retired_dragon 3 · 0⤊ 0⤋
csc(B) = 1/sin(B) = 5sqrt3/5sqrt2 = sqrt3/sqrt2
Why would you have the problem with 5 in numerator and denominator, it would cancel?
2006-08-30 16:40:31 · answer #4 · answered by Anonymous · 0⤊ 0⤋
csc B = 1/(5sqrt2/5sqrt3)
substituting:
= 1/.82
= 1.22
i hope i got it right.. :)
2006-08-30 16:44:37 · answer #5 · answered by Angelica 2 · 0⤊ 0⤋
sqrt3/sqrt2
csc = 1/sin
2006-08-30 16:38:05 · answer #6 · answered by eric r 2 · 1⤊ 0⤋
sinB = (2/3)^(1/2)
cscB = (3/2)^(1/2)
2006-08-30 16:46:47 · answer #7 · answered by knowbuddycares 3 · 0⤊ 0⤋
sqrt3/sqrt2
2006-08-30 16:51:13 · answer #8 · answered by LoneWolf 3 · 0⤊ 0⤋
ummmmmmmmmmm......4!
2006-08-30 16:38:16 · answer #9 · answered by ? 6 · 0⤊ 0⤋