(3x-2)/(x-5)=2
mulltiply both sides by (x-5)
(3x-2)/(x-5)] (x-5)= 2(x-5)
3x-2=2x-10
subtract 2x from both sides
(3x-2)-2x=(2x-10)-2x
x-2=-10
x=NEGATIVE 8
(3)(-8)-2\ ((-8-5)=2
(-24-2)\(-13)=2
-26\-13=2
then to check your work you plug -8 in where x is.
2006-08-30 09:27:32
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answer #1
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answered by Anonymous
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Multiply both sides by (x-5) to get:
3x - 2 = 2 (x - 5)
3x - 2 = 2x - 10
x -2 = - 10
x = -8.
2006-08-30 16:19:26
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answer #2
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answered by -j. 7
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It is: FOIL
3x(x) and 3x(5)
2 (x) and 2(5)
x=-8
2006-08-30 16:18:03
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answer #3
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answered by Anonymous
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3x-2 = 2 (x-5)
3x-2 = 2x-10
x = -8
Hope this helps!
2006-08-30 16:21:22
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answer #4
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answered by camellia_ 2
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x=-8
2006-08-30 16:18:46
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answer #5
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answered by predhead33 3
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-8
2006-08-30 16:28:24
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answer #6
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answered by dex 1
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3x-2=2x-10
3x-2x=-10+2
x=-8...
Therefore, x = -8...
2006-08-30 16:18:56
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answer #7
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answered by ShaH 6
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math sucks !! big time
2006-08-30 16:18:16
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answer #8
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answered by Anonymous
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