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how do i solve this?
|10-3x| + 5 = 2

2006-08-30 08:45:28 · 7 answers · asked by Anonymous in Science & Mathematics Mathematics

7 answers

let y = |10 - 3x|

y + 5 = 2
y = -3

|10 - 3x| = -3

uhhh .... no value of x will make |10 - 3x| be less than zero.

answer" "no solution"

2006-08-30 08:54:20 · answer #1 · answered by atheistforthebirthofjesus 6 · 0 1

There are two answers. |10-3x| means 10-3x or -10+3x so

10-3x + 5 = 2 => -3x = 2 - 15 => -3x = -13 => x = 13/3

-10 + 3x + 5 = 2 => 3x = 2 + 5 => 3x = 7 => x = 7/3

2006-08-30 15:56:22 · answer #2 · answered by gp4rts 7 · 0 0

Absolute values means there are 2 solutions; a negative and a positive.

So let us look at it this way:

l10-3xl = -3 (by subtracting 5 from both sides)

Now we will work this equation 2 ways, since absolute value can have 2 solutions.

10-3x = -3 AND 10-3x = 3
-3x = -13; -3x = -7

x = (13/3); x = (7/3)


Those are your solutions.

2006-08-30 17:14:34 · answer #3 · answered by mthtchr05 5 · 0 0

Ok let see.look darling, you need to simplify this function.

● Explanation ;
{
if y= | x | means
◊ x>0
OR
◊ x<0
} ...

so ' -10 +3x & 10 - 3x '

▪ |10-3x| =2-5
▪ -10 +3x = 2-5 ; 3x= -3 +10 ; 3x= 7 ; x = 7/3 = 2.3
▪ +10 -3x =2-5 ; -3x= -3 -10 ; 3x= -13 ; x =-13/3 = - 4.3
Good luck.

2006-08-30 16:19:22 · answer #4 · answered by sweetie 5 · 0 0

|10 - 3x| + 5 = 2
|10 - 3x| = -3

Since the result of |y| can only be positive

ANS : No Solution

2006-08-31 00:18:37 · answer #5 · answered by Sherman81 6 · 0 0

Isolate the absolute value term on one side of the equation.
Then create two equations, one using the value on the right hand side and the other using the value on the right hand side multiplied by (-1). Left hand side in each equation is the absolute value term without the brackets.

2006-08-30 15:52:49 · answer #6 · answered by Helmut 7 · 0 0

|10-3x| = -3
3x = -3 -10
x = -13/3

i think

2006-08-30 15:50:12 · answer #7 · answered by Anonymous · 0 0

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