can i have help on these sort of questions?

Question

a ball of mass 8kg compresses a spring 1cm, if the spring is compressed another 1cm and released how high will the ball reach. i am looking for information on springs and what the initial velocity of an object released from a spring will be if given a certain force

Answer 1

OK. The spring constant (k) is obviously 78.4 N/cm. The total energy contained in the spring is k*x²/2 Joules. Calculate the total energy in the spring at equilibrium (when the mass compresses it 1 cm) and subtract that from the total energy stored when the spring is compressed 2 cm. The difference will be the total energy imparted to the mass in an 'upwards' direction. It will also be equal to m*g*h where m is the mass, g is 9.8 m/s² (the acceleration of gravity) and h is the height above the equilibrium point that the mass will attain. Make sure all of your distances are in meters. (1 cm = .01 m)


Doug

Answer 2

we need more information here............my physics is a little rusty but I think we need to know stuff like the original length of the spring, young's modulus, stuff like that. I've got to say though that depressing an 8kg mass by only 2cm on any spring I've ever seen wouldn't produce much of a bounce, more of a gentle rocking motion!