Help on Algebra II Honors HW please!?

Question

NO I'm not asking you to solve it for me, just tell me what the heck I'm supposed to do lol.


V=(pi/3)r^2h (Solve for H)



How the heck do I do that???

Answer 1

I'm going to assume you mean:

V = (pi/3) * r^2 * h

In this case, you need to divide both sides by (pi/3):

3V/pi = r^2 * h

And then divide both sides by r^2:

3V / (pi * r^2) = h

And you've solved for h. If, however, you meant:

V = (pi/3) * r^(2h)

It's more complicated. Still, divide both sides by (pi/3)

3V/pi = r^(2h)

And now you need to take the log (base r) of both sides.

log-base-r(3V/pi) = 2h

Now just divide by 2.

[log-base-r(3V/pi)] / 2 = h

And there you have it. Log is an inverse of exponentation, so it's the only thing you can use in a situation like that. I don't know which form of the question you asked, it wasn't very clear... But hopefully this helps. Good luck!

Answer 2

pi=22/7 or 3.14. I'll use 3.14

(3.14 divided by 3)x r to the power of 2 x h

There is a rule for this.
First, eliminate thing in parenthesis.
Then, eliminate the powers.
Next, multiplication and division.
Finally, addition and substraction.
Everything donde from left to right.

Answer 3

I took fairly the comparable scheldue numerous artwork sometimes staying up fairly late to examine or end hw yet i did fairly solid i think of i've got been given all a's and one b, i nevertheless had time to do issues interior the weekend

Answer 4

Basically, get h on one side, everything else on the other :)

Step 1 : 3V = pi * r^2 * h

Step 2 : ?????

Step 3 : PROFIT.

Answer 5

V = (1/3)pi * r^2 * h

3V = pi * r^2 * h

h = (3V)/(pi * r^2) or 3(V/(pi * r^2))

Answer 6

Rearrange, and you'll see it right away:

V = (pi r^2 h) / 3

Now solve for h.

Answer 7

The symbols arent clear enof. it sounds quite easy.

Answer 8

Hawk22 has given you correct answer.

Answer 9

You just do the operations that will makes the equation...

h = ?