[7(5-3)^2 + 14] (8+3 * 18)
_____________________
2^2 (2^4 -9)
A) 115
B)64
C)93
d)100
I can;t seem to get the right answer.. can anyone help
2006-08-30 05:39:37 · 3 answers · asked by laural8477 3 in Education & Reference ➔ Homework Help
Remember operation order rules...
[7(5-3)^2 + 14] = 42
(5-3) first, ^2 second, *7 third, + 14 fourth
(8+3*18) = 62
3*18 first, + 8 second
2^2 (2^4 - 9) = 28
2^4 first, - 9 second, * 2^2 third
42 * 62 = 2604
2604 / 28 = 93
2006-08-30 05:52:26 · answer #1 · answered by Professor 3 · 0⤊ 0⤋
Answer is C) 93
[7(5-3)^2]=[7*2^2]=28
[8+3*18]=8+54=62
[2^4-9]=16-9=7
([28+14]*62)/(4*7) = 93
2006-08-30 12:58:14 · answer #2 · answered by Stillmatic 1 · 0⤊ 0⤋
The denominator is 28: (4*(16-9))
The is [7(2)^2+14](8+3*18) which is 2604
the answer is 93
2006-08-30 12:55:51 · answer #3 · answered by odu83 7 · 0⤊ 0⤋