y=square root of x - 2x x= -1, x=0, x=1, x=1/4, x= -3?

Answer 1

if x=-1, then y=1

if x=0, then y=0

if x=1,then y=i where i is an imaginary number

if x=1/4, then y=0.5*i where i is an imaginary number

if x=-3, then y=1.7321

Answer 2

I don't know which one you mean, but if your formula is one of:

1) Y = sqrt(x - 2x)
2) Y = sqrt(x) - 2x

All you have to do is, plug the X value into the formula and compute the Y value. Remember, if you take a square root of a value, your solution is + or -. For example, sqrt(4) is +2 or -2. So, you get two Y values for every X.

The only exception is X=0 where sqrt(0) is zero.

Answer 3

You have the values for x. Just plug them into your equation and solve for y.
Using -1, x-2x = -1 - (2*-1) = -1 +2 = 1. So, y= sq. rt. of 1 which is 1

Answer 4

sqrt=squareroot
Y=sqrt(x-2x)

At x = -1
Y =sqrt[(-1)-2(-1)]
=1

At x=0
Y =sqrt[(0)-2(0)]
=0

At x =1
Y =sqrt[(1)-2(1)]
= I, where I is an imaginary number

At x =1/4
Y =sqrt[(1/4)-2(1/4)]
=1/2 I, where I is an imaginary number

At x=-3
Y =sqrt[(-3)-2(-3)]
=sqrt 3 in exact form or = 1.7321 to 4 decimal places

Answer 5

4(x - 12) = -4(14 - x) 4x - 40 8 = -56 + 4x 4x - 4x = -56 + 40 8 0x = -8 0 = -8 (pretend) there is not any answer to this equation, which means that no x can fulfill this equation. therefore, the answer set is empty.

Answer 6

y = sqrt of -x
being
1,AHHH,i,i/16,sqrt 3
respectivly

Answer 7

0
your answer is zero

Answer 8

your all answers are wrong,right ans . is= y^=-x