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A small can weigh 1.23N in air and has a volume of 1 X 10 -5 m3. How much will it weigh when completely submerged in water? Pls show solution. Thats 10 to the negative 5th power

2006-08-30 02:06:08 · 2 answers · asked by donann 2 in Science & Mathematics Physics

2 answers

Let water's density = 1000kg/m^3

So, wt. in water = 1.23 - 10^-5*10^3*9.8 = 1.13 N approx.

2006-08-30 02:17:39 · answer #1 · answered by ag_iitkgp 7 · 0 0

New weight = 1.23 - (equavilent weight of water of 1x10-5m3)

2006-09-02 01:43:44 · answer #2 · answered by dwarf 3 · 0 0

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