2006-08-30 01:58:05 · 20 answers · asked by SHIVANI J 1 in Science & Mathematics ➔ Mathematics
we have to find
5a-3b/5a+3b if we apply BODMAS rule then division should come first as there is no bracket in the question, then
5a-3*3/5*5+3b
5a-9/25+3b
5a+3b-9/25
5*5b/3+3b-9/25
25b/3+3b-9/25
so above que cannot be solved completely as one variable will always remains there.
2006-08-30 08:49:20 · answer #1 · answered by shadab n 3 · 0⤊ 0⤋
Multiplying both sides by 5*3, we get 5a:3b=25:9. Then by componendo and dividendo, 5a+3b/5a-3b=34/16. Divide it by 1. The answer is 16/34=8/17.
2006-08-30 09:06:12 · answer #2 · answered by Urvashi B 1 · 0⤊ 0⤋
5b = 3a and hence b = 3/5 a
Substituting the valu of b in 5a-3b/5a+3b we get 8/17
2006-08-30 09:08:16 · answer #3 · answered by rajr59 2 · 0⤊ 0⤋
a:b=5:3
=>a/b=5/3
=>5a/3b=25/9
=>5a-3b/5a+3b=8/17
2006-08-31 11:44:48 · answer #4 · answered by avik r 2 · 0⤊ 0⤋
(5a-3b)/(5a+3b) = (5a/b - 3)/(5a/b + 3) = (25/3 - 3)/(25/3 + 3)
= (25-9)/(25+9) = 16/34 = 8/17
2006-08-30 09:10:06 · answer #5 · answered by ag_iitkgp 7 · 0⤊ 0⤋
if you read the question as it is...then:
5a ~ 5*5 = 25
3b/5a ~ (3*3)/(5*5) = 9/25
3b ~ 3*3 = 9
25 - 9/25 + 9 = 33 16/25
if you meant (5a-3b)/(5a+3b), then see the first person gave
2006-08-30 09:08:17 · answer #6 · answered by Blind Wing 3 · 1⤊ 0⤋
8/17
2006-08-30 13:40:09 · answer #7 · answered by king64_shahab 2 · 0⤊ 0⤋
8/17
2006-08-30 11:37:35 · answer #8 · answered by Dheepak 2 · 0⤊ 0⤋
8/17
2006-08-30 10:21:54 · answer #9 · answered by pcasthana2003 1 · 0⤊ 0⤋
8/17
2006-08-30 09:22:29 · answer #10 · answered by nmirgane 1 · 0⤊ 0⤋