2006-08-30 01:51:14 · 7 answers · asked by Desert Storm 1 in Science & Mathematics ➔ Mathematics
x^4-x = x(x^3-1) = x(x-1)(x^2+x+1)
2006-08-30 02:06:53 · answer #1 · answered by ag_iitkgp 7 · 0⤊ 0⤋
x^4 - x = x(x^3 - 1) = x(x - 1)(x^2 + x + 1)
2006-08-30 15:21:34 · answer #2 · answered by Sherman81 6 · 0⤊ 0⤋
x^4 - x
= x(x^3 - 1)
= x(x - 1)(x^2 + x + 1)
2006-08-30 11:12:38 · answer #3 · answered by ideaquest 7 · 0⤊ 0⤋
x^4 - x
= x(x^3 - 1)
= x(x - 1)(x^2 + x + 1)
2006-08-30 10:20:21 · answer #4 · answered by bassbredrin 2 · 0⤊ 0⤋
x^4-x=
x(x^3-1)
2006-08-30 09:14:54 · answer #5 · answered by A 4 · 0⤊ 0⤋
x(x^3-1)
2006-08-30 08:56:48 · answer #6 · answered by pacrady 2 · 0⤊ 0⤋
x^4-x
= x(x^3-x)
= x(x-1)(x^2+x+1) [since, a^3-b^3=(a-b)(a^2+ab+b^2)]
2006-08-30 08:59:39 · answer #7 · answered by Anonymous · 0⤊ 0⤋